所以我有一个多维数组,如:
myArr = [["venue",2],["venue",16],["inning",2],["inning",4],["inning",32],["hithard", 4]]
我想添加类似的值。所以最后我才有:
"venue" = 18, "inning" = 38, and "hithard" = 4.
你能举个例子说明如何做到这一点吗?使用Javascript和/或jQuery
谢谢!
答案 0 :(得分:3)
myArr = [["venue",2],["venue",16],["inning",2],["inning",4],["inning",32],["hithard", 4]];
values = {};
for (i=0;i<myArr.length;i++){
if ("undefined" == typeof values[myArr[i][0]]) {values[myArr[i][0]] = 0;}
values[myArr[i][0]] += myArr[i][1];
}
arr = [];
query_string = "";
for (i in values) {
// if you want it in an array:
arr.push('"' + i + '" = ' + values[i]);
query_string += (query_string.length ? "&" : "") + i + "=" + values[i];
}
console.log(arr);
DEMO:http://jsfiddle.net/Ta97E/2/
您可以使用值来创建查询字符串
答案 1 :(得分:3)
我不确定您是否需要数组或对象。如果是对象,请将其停止为第一遍,并且下面的代码中的tmp
应该将对象作为Object { venue=18, inning=38, hithard=4}
返回给您。
var tmp = {}, keys;
for (var i = 0; i < myArr.length; i++) {
keys = myArr[i][0];
tmp[keys] = (tmp.hasOwnProperty(keys))?
(tmp[keys] + myArr[i][1]):myArr[i][1];
} //tmp - will return you a Object { venue=18, inning=38, hithard=4}
var output = [];
for (keys in tmp) {
output.push([keys, tmp[keys]]);
} //output will return you an array as [["venue", 18],["inning", 38],["hithard", 4]]
答案 2 :(得分:2)
检查此代码:
var final = {};
for (var i in myArr) {
var item = myArr[i];
final[item[0]] = (final[item[0]] || 0) + item[1];
}
console.log(final);
答案 3 :(得分:2)
Underscore解决方案:
sums = _.reduce(myArr, function (obj, item) {
obj[item[0]] = (obj[item[0]] || 0) + item[1];
return obj;
}, {});
// sums = {"venue":18,"inning":38,"hithard":4}
jQuery中的一点点肮脏
sums = {}
$.each(myArr, function (i, value) {
sums[value[0]] = (sums[value[0]] || 0) + value[1];
});
编辑:添加jQuery版本