Question

我正在尝试编写一个解析算法来有效地从xml文档中提取数据。我目前正在浏览基于元素和子元素的文档，但是想使用iterparse。一个问题是我有一个元素列表，当我找到它时，我想从它们中提取子数据，但似乎使用iterparse我的选项是根据一个元素名称进行过滤，或者获取每个元素。

示例xml：

<?xml version="1.0" encoding="UTF-8"?>
<data_object xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
 <source id="0">
  <name>Office Issues</name>
  <datetime>2012-01-13T16:09:15</datetime>
  <data_id>7</data_id>
 </source>
 <event id="125">
  <date>2012-11-06</date>
  <state_id>7</state_id>
 </event>
 <state id="7">
  <name>Washington</name>
 </state>
 <locality id="2">
  <name>Olympia</name>
  <state_id>7</state_id>
  <type>City</type>
 </locality>
 <locality id="3">
  <name>Town</name>
  <state_id>7</state_id>
  <type>Town</type>
 </locality>
</data_object>

代码示例：

from lxml import etree

fname = "test.xml"
ELEMENT_LIST = ["source", "event", "state", "locality"]

with open(fname) as xml_doc:
    context = etree.iterparse(xml_doc, events=("start", "end"))

    context = iter(context)

    event, root = context.next()

    base = False
    b_name = ""

    for event, elem in context:
        if event == "start" and elem.tag in ELEMENT_LIST:
            base = True
            bname = elem.tag
            children = elem.getchildren()
            child_list = []
            for child in children:
                child_list.append(child.tag)
            print bname + ":" + str(child_list)
        elif event == "end" and elem.tag in ELEMENT_LIST:
            base = False
            root.clear()

Answer 1

使用iterparse，您不能将解析限制为某些类型的标记，您只能使用一个标记（通过传递参数tag）。但是，您可以轻松地手动完成您想要实现的目标。在以下代码段中：

from lxml import etree

fname = "test.xml"
ELEMENT_LIST = ["source", "event", "state", "locality"]

with open(fname) as xml_doc:
    context = etree.iterparse(xml_doc, events=("start", "end"))

    for event, elem in context:
        if event == "start" and elem.tag in ELEMENT_LIST:
            print "this elem is interesting, do some processing: %s: [%s]" % (elem.tag, ", ".join(child.tag for child in elem))
        elem.clear()

您只能将搜索限制为有趣的标签。 iterparse的重要部分是elem.clear()，它在项目过时时清除内存。这就是内存效率的原因，请参阅http://lxml.de/parsing.html#modifying-the-tree

Answer 2

我会改用XPath。它比你自己走文件要优雅得多，而且我假设效率更高。

Answer 3

使用tag='{http://www.sitemaps.org/schemas/sitemap/0.9}url'

与正确答案相似的问题https://stackoverflow.com/a/7019273/1346222

#!/usr/bin/python
# coding: utf-8
""" Parsing xml file. Basic example """
from StringIO import StringIO
from lxml import etree
import urllib2

sitemap = urllib2.urlopen(
    'http://google.com/sitemap.xml',
    timeout=10
).read()


NS = {
    'x': 'http://www.sitemaps.org/schemas/sitemap/0.9',
    'x2': 'http://www.google.com/schemas/sitemap-mobile/1.0'
}


res = []

urls = etree.iterparse(StringIO(sitemap), tag='{http://www.sitemaps.org/schemas/sitemap/0.9}url')

for event, url in urls:
    t = []
    t = url.xpath('.//x:loc/text() | .//x:priority/text()', namespaces=NS)
    t.append(url.xpath('boolean(.//x2:mobile)', namespaces=NS))
    res.append(t)

使用lxml和iterparse获取子元素

3 个答案: