Question

我有一个带有x和y轴的简单图形。我不希望我在其中绘制的绘图区域与轴重叠。

我正在使用d3创建我的图表，但剪辑路径不起作用：

var margin = {top: 19.5, right: 19.5, bottom: 19.5, left: 39.5},
    width = 960 - margin.right,
    height = 500 - margin.top - margin.bottom;

var xScale = d3.scale.linear().
    domain([xMin, xMax]). // your data minimum and maximum
    range([0, width]); // the pixels to map to, e.g., the width of the diagram.

var yScale = d3.scale.linear().
    domain([yMax, yMin]). 
    range([0, height]); 

var xAxis = d3.svg.axis().orient("bottom").scale(xScale).ticks(10, d3.format(",d")),
    yAxis = d3.svg.axis().orient("left").scale(yScale);


var chart = d3.select("#chart").append("svg")
    .attr("class", "chart")
    .attr("width", width + margin.left + margin.right)
    .attr("height", height + margin.top + margin.bottom)
    .attr("pointer-events", "all")
    .append("g")
    .attr("transform", "translate(" + margin.left + "," + margin.top + ")")
    .call(d3.behavior.zoom().scaleExtent([0.2, 5]).on("zoom", redraw));


var rect = chart.append('svg:rect')
    .attr('width', width)
    .attr('height', height)
    .attr('fill', 'white');


var line = d3.svg.line()
        .interpolate("basis")
        .x(function(d, i) { return xScale(d.time); })
        .y(function(d) { return yScale(d.value); });

var clip = chart.append("svg:clipPath")
    .attr("id", "clip");

clip.append("svg:rect")
    .attr("id", "clip-rect")
    .attr("width", width)
    .attr("height", height);
    // .attr("fill", "white");

var path = chart.append("svg:path")
    .attr("clip-path", "url(#clip-rect)")
    .data([data])
    .attr("class", "line")
    .attr("fill", "none")
    .attr("stroke", "maroon")
    .attr("stroke-width", 2)
    .attr("d", line);

// x-axis label
chart.append("text")
    .attr("class", "x label")
    .attr("text-anchor", "end")
    .attr("x", width)
    .attr("y", height - 6)
    .text("time");

// y-axis label
chart.append("text")
    .attr("class", "y label")
    .attr("text-anchor", "end")
    .attr("y", 6)
    .attr("dy", ".75em")
    .attr("transform", "rotate(-90)")
    .text("value");

// x-axis
var xaxis = chart.append("g")
    .attr("class", "x axis")
    .attr("transform", "translate(0," + height + ")")
    .call(xAxis);

// y-axis
var yaxis = chart.append("g")
    .attr("class", "y axis")
    .call(yAxis);



function redraw() 
{
    console.log("here", d3.event.translate, d3.event.scale);

    path.transition()       
        .ease("linear")
        .attr("transform", "translate(" + d3.event.translate + ")" + " scale(" + d3.event.scale + ")");

}

Answer 1

你想要这样的东西：

http://jsfiddle.net/dsummersl/EqLBJ/1/

具体做法是：

使用'clip'代替'clip-rect'
将您要剪辑的内容放在'g'元素中，并指定'clip-path'属性和'g'元素的变换。

矩形内的Svg剪辑路径不起作用

1 个答案: