我正在尝试使用以下代码计算47 x 3
规范化设计矩阵X
的列总和:
sum(X)
以下是X
的内容:
X =
1.0000e+00 1.3001e-01 -2.2368e-01
1.0000e+00 -5.0419e-01 -2.2368e-01
1.0000e+00 5.0248e-01 -2.2368e-01
1.0000e+00 -7.3572e-01 -1.5378e+00
1.0000e+00 1.2575e+00 1.0904e+00
1.0000e+00 -1.9732e-02 1.0904e+00
1.0000e+00 -5.8724e-01 -2.2368e-01
1.0000e+00 -7.2188e-01 -2.2368e-01
1.0000e+00 -7.8102e-01 -2.2368e-01
1.0000e+00 -6.3757e-01 -2.2368e-01
1.0000e+00 -7.6357e-02 1.0904e+00
1.0000e+00 -8.5674e-04 -2.2368e-01
1.0000e+00 -1.3927e-01 -2.2368e-01
1.0000e+00 3.1173e+00 2.4045e+00
1.0000e+00 -9.2196e-01 -2.2368e-01
1.0000e+00 3.7664e-01 1.0904e+00
1.0000e+00 -8.5652e-01 -1.5378e+00
1.0000e+00 -9.6222e-01 -2.2368e-01
1.0000e+00 7.6547e-01 1.0904e+00
1.0000e+00 1.2965e+00 1.0904e+00
1.0000e+00 -2.9405e-01 -2.2368e-01
1.0000e+00 -1.4179e-01 -1.5378e+00
1.0000e+00 -4.9916e-01 -2.2368e-01
1.0000e+00 -4.8673e-02 1.0904e+00
1.0000e+00 2.3774e+00 -2.2368e-01
1.0000e+00 -1.1334e+00 -2.2368e-01
1.0000e+00 -6.8287e-01 -2.2368e-01
1.0000e+00 6.6103e-01 -2.2368e-01
1.0000e+00 2.5081e-01 -2.2368e-01
1.0000e+00 8.0070e-01 -2.2368e-01
1.0000e+00 -2.0345e-01 -1.5378e+00
1.0000e+00 -1.2592e+00 -2.8519e+00
1.0000e+00 4.9477e-02 1.0904e+00
1.0000e+00 1.4299e+00 -2.2368e-01
1.0000e+00 -2.3868e-01 1.0904e+00
1.0000e+00 -7.0930e-01 -2.2368e-01
1.0000e+00 -9.5845e-01 -2.2368e-01
1.0000e+00 1.6524e-01 1.0904e+00
1.0000e+00 2.7864e+00 1.0904e+00
1.0000e+00 2.0299e-01 1.0904e+00
1.0000e+00 -4.2366e-01 -1.5378e+00
1.0000e+00 2.9863e-01 -2.2368e-01
1.0000e+00 7.1262e-01 1.0904e+00
1.0000e+00 -1.0075e+00 -2.2368e-01
1.0000e+00 -1.4454e+00 -1.5378e+00
1.0000e+00 -1.8709e-01 1.0904e+00
1.0000e+00 -1.0037e+00 -2.2368e-01
总和:
ans =
4.7000e+01 1.0885e-15 1.2684e-14
第1列的总和是正确的,但其他的却是正确的。有什么想法吗?
答案 0 :(得分:0)
第2列和第3列看起来像是大约为零。每个元素都是浮点值,有时在添加和减去浮点数时会丢失一些精度。而不是看到零,你只是看到一个非常小的数字(10 ^ -15!)。一个简单的解决方法是将所有低于某个阈值的数字设置为零:
mysum = sum(X);
mysum(mysum < 1e-12) = 0
ans =
47.0000 0 0