Question

我有以下SQL：

SELECT `table1`.`value`, `table2`.* 
FROM `table2` 
INNER JOIN `table1` ON `table2`.`product_id` = `table1`.`entity_id`
WHERE `table2`.`created_at` > '2012-04-23' and 
(`table1`.`value` = 264 OR `table1`.`value` = 260)
order by order_id

返回这样的结果集（这只是返回结果的一部分）：

value  order_id   ...
260    1234
260    1235
260    1236
264    1236
260    1237
260    1238
260    1239
264    1239
264    1240
260    1241

我想要的是一个查询，它将获取这些结果，并且只返回order_id包含值260和264的订单。基于此示例，我要查找的最终结果是

我的想法是这可以用一个子集完成，但我不完全确定完成它的细节。

Answer 1

这可以通过relational division完成：

select r.order_id from (
  select 
    dividend.*  
  from your_table_or_query as dividend  -- assumes no duplicates in `dividend`; use `distinct` if there are any
  inner join divisor
  on dividend.value = divisor.value
) as r
group by r.order_id
having count(*) = (select count(*) from divisor);

结果：

+----------+
| order_id |
+----------+
|     1236 |
|     1239 |
+----------+
2 rows in set (0.00 sec)

您的查询为your_table_or_query和

select 260 as value from dual union select 264 as value from dual

是divisor。

这将返回订单ID 1236和1239;然后，他们可以join到原始查询，以获取具有这些订单ID的所有行，如果这是您想要的。

完整查询以及插入语句：

create table divisor (value int);
insert into divisor values (260), (264);

create table your_table_or_query (value int, order_id int);
insert into your_table_or_query values (260, 1234), (260, 1235), (260, 1236), (264, 1236), (260, 1237), (260, 1238), (260, 1239), (264, 1239), (264, 1240), (260, 1241);


select y.* from (
  select r.order_id from (
    select
      dividend.*
    from your_table_or_query as dividend
    inner join divisor
      on dividend.value = divisor.value
  ) as r 
  group by r.order_id
  having count(*) = (select count(*) from divisor)
) as quotient
inner join your_table_or_query y
  on quotient.order_id = y.order_id;

结果：

+-------+----------+
| value | order_id |
+-------+----------+
|   260 |     1236 |
|   264 |     1236 |
|   260 |     1239 |
|   264 |     1239 |
+-------+----------+
4 rows in set (0.00 sec)

Answer 2

这个怎么样？

SELECT table1.value, table2.* 
FROM table2 
INNER JOIN table1 
ON table2.product_id = table1.entity_id
WHERE table2.created_at > '2012-04-23' AND
(table1.value = 264 OR table1.value = 260)
AND table2.order_id IN (
    SELECT table2.order_id  
    FROM table2 
    INNER JOIN table1 
    ON table2.product_id = table1.entity_id
    WHERE table2.created_at > '2012-04-23' AND
    (table1.value = 264 OR table1.value = 260)
    GROUP BY table2.order_id
    HAVING COUNT(*) = 2
)

（抱歉省略撇号，我不知道这个字段中的mysql要求是什么;这个语法符合ms-sql）

Answer 3

这将返回一个包含值260和264的订单列表 - 如果有人只需要此结果而不是每个值的重复结果：

SELECT `table2`.* 
FROM `table2` 
INNER JOIN `table1` as `table1_264`
  ON `table2`.`product_id` = `table1_264`.`entity_id`
  AND `table1_264`.`value` = 264
INNER JOIN `table1` as `table1_260`
  ON `table2`.`product_id` = `table1_260`.`entity_id`
  AND `table1_260`.`value` = 260
WHERE `table2`.`created_at` > '2012-04-23'
order by order_id

<小时/> 或者如果有人想要更快的解决方案而没有昂贵的having条款（当然，你可以存储查询或使用CTE而不是重复它）

SELECT 264 as `value`, `table2`.* 
 FROM `table2` 
 INNER JOIN `table1` as `table1_264` ON `table2`.`product_id` = `table1_264`.`entity_id` AND `table1_264`.`value` = 264
 INNER JOIN `table1` as `table1_260` ON `table2`.`product_id` = `table1_260`.`entity_id` AND `table1_260`.`value` = 260
 WHERE `table2`.`created_at` > '2012-04-23'
UNION ALL
SELECT 260, `table2`.* 
 FROM `table2` 
 INNER JOIN `table1` as `table1_264` ON `table2`.`product_id` = `table1_264`.`entity_id` AND `table1_264`.`value` = 264
 INNER JOIN `table1` as `table1_260` ON `table2`.`product_id` = `table1_260`.`entity_id` AND `table1_260`.`value` = 260
 WHERE `table2`.`created_at` > '2012-04-23'
order by order_id

Answer 4

SELECT `table1`.`value`, `table2`.* 
FROM `table1` 
LEFT JOIN `table2` ON `table1`.`entity_id` = `table2`.`product_id`
WHERE
(`table1`.`value` = 264 OR `table1`.`value` = 260)
AND `table2`.`created_at` > '2012-04-23' 
ORDER BY `table2`.order_id

左连接因此它只匹配table1.value结果与匹配并保留其他表中的信息

SQL返回合并的结果集

4 个答案: