Question

我在这里收到以下错误：

        Line 45:         <tr>
        Line 46:             <td width="15%" valign="top">
        Line 47:                 @{Html.RenderAction("GetMenu","RoomType");}
        Line 48:             </td>
        Line 49:             <td valign="top"


 'The model item passed into the dictionary is of type   
 'System.Collections.Generic.List`1[System.Object]', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[LicentaTest.Models.RoomType]'.

我不知道我错在哪里。这是来自RoomTypecontroller的GetMenu方法：

      'public ActionResult GetMenu()
        {
        DBContext.Current.Open();
        var model =RoomType.SelectAll();
        DBContext.Current.Close();
        return PartialView(model);
         }'

这是我的获取菜单视图：

      @model IEnumerable<LicentaTest.Models.RoomType>
      @using LicentaTest.Models
      <script type="text/javascript">
      $(function () {
      $("#categories").addClass("ui-widget");
      $("a", "#categories").button().width(200);
      });
      </script>
      <ul id="categories">
      @foreach (var tipcamera in Model) 
      { 
<li>@Html.ActionLink(tipcamera.Room_Type,"Browse","RoomType",new{RoomType=tipcamera.Room_Type},null)
       </li>


        }

Answer 1

其实我不知道你的RoomType.SelectAll()做了什么，但我想它会以任何方式返回List<object>尝试它应该有效：

var model = RoomType.SelectAll().Cast<RoomType>();

传递到字典中的模型项的类型为'System.Collections.Generic.List ErroR

1 个答案: