Question

我想根据周将多行转换为单行。它应该如下所示。任何人都可以帮助我吗？

id      |   Weight   |  Created   |
 1      |    120     | 02-04-2012 |
 2      |    110     | 09-04-2012 |
 1      |    100     | 16-04-2012 |
 1      |    130     | 23-04-2012 |
 2      |    140     | 30-04-2012 |
 3      |    150     | 07-05-2012 |

结果应如下所示：

id      |   Weight_week1  | Weight_week2  |  weight_week3  | weight_week4  |
 1      |     120         |     100       |      130       |               |
 2      |     110         |     140       |                |               |
 3      |     150         |               |                |               |

提前致谢。

Answer 1

你可以这样做：

SELECT
    t.id,
    SUM(CASE WHEN WeekNbr=1 THEN Table1.Weight ELSE 0 END) AS Weight_week1,
    SUM(CASE WHEN WeekNbr=2 THEN Table1.Weight ELSE 0 END) AS Weight_week2,
    SUM(CASE WHEN WeekNbr=3 THEN Table1.Weight ELSE 0 END) AS Weight_week3,
    SUM(CASE WHEN WeekNbr=4 THEN Table1.Weight ELSE 0 END) AS Weight_week4
FROM
    (
    SELECT  
        (
           WEEK(Created, 5) - 
           WEEK(DATE_SUB(Created, INTERVAL DAYOFMONTH(Created) - 1 DAY), 5) + 1 
        )as WeekNbr,
        Table1.id,
        Table1.Weight,
        Table1.Created
    FROM
        Table1
    ) AS t
GROUP BY
    t.id

我不知道您是想要AVG，SUM，MAX还是MIN，但您可以将汇总更改为您想要的内容。

有用的参考资料：

Function for week of the month in mysql

Answer 2

如果这是一张表，那么

SELECT GROUP_CONCAT(weight) as Weight,
        WEEK(Created) as Week
Group by Week(Created)

这将为您提供一行，每行都有周id和逗号分隔的whights

Answer 3

你不能像这样动态创建字段，但你可以将它们分组。

使用GROUP_CONCAT通过分隔符提供结果，以后可以分开。

Answer 4

你也可以这样做：

SELECT id, created, weight, (
    SELECT MIN( created ) FROM weights WHERE w.id = weights.id
) AS `min` , round( DATEDIFF( created, (
   SELECT MIN( created )
FROM weights
WHERE w.id = weights.id ) ) /7) AS diff
FROM weights AS w
ORDER BY id, diff

此代码不执行数据透视表。您应该添加一些额外的代码来将数据转换为您的需求。如果因使用年限而使用WEEK（），则可能会遇到麻烦。

MySQL：如何将多行转换为单行？在mysql中

4 个答案: