我在C#中遇到正常的DES加密问题,我想要一个16字符长度(16字节128位)的输出字符串,它只包含字母和数字字符。
答案 0 :(得分:1)
如果限制为只包含字母数字字符的16个字符输出,则表示您有~95位可用输出空间(如果您可以使用Base-64编码,则恰好为96位,即包含2个非字母数字字符)
因此,您无法做任何事情,只允许您使用此限制加密超过95位。如果这对你来说已经足够了,那就有可能。
像这样的东西(CTR模式下的3DES)是一个如何工作的例子(使用Base-64),但正如上面评论中所述,它实际上取决于你真正想做的事情。
void Main()
{
var data = new byte[] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 };
var key = new byte[] { 01, 12, 23, 34, 45, 56, 67, 78, 89, 90, 09, 98, 87, 76, 65, 54, 43, 32, 21, 10, 11, 22, 33, 44 };
var encrypted = Encrypt(data, key, 0);
Console.WriteLine(encrypted);
var decrypted = Decrypt(encrypted, key, 0);
// decrypted should be equal to data here
}
public string Encrypt(byte[] data, byte[] key, long nonce)
{
return Convert.ToBase64String(Transform(data, key, nonce));
}
public byte[] Decrypt(string data, byte[] key, long nonce)
{
return Transform(Convert.FromBase64String(data), key, nonce);
}
byte[] Transform(byte[] data, byte[] key, long nonce)
{
if (data.Length > 96/8) throw new ArgumentException("Too much data");
using (var des = new TripleDESCryptoServiceProvider())
{
des.Key = key;
des.Mode = CipherMode.ECB;
using (var encryptor = des.CreateEncryptor())
{
var output = new byte[data.Length];
var offset = 0;
for(int counter = 0; counter <= data.Length / 8; ++counter)
{
var counterData = BitConverter.GetBytes(((long)counter) ^ nonce);
var counterEncryption = new byte[des.BlockSize / 8];
var counterEncryptionLen = encryptor.TransformBlock(counterData, 0, counterData.Length, counterEncryption, 0);
Debug.Assert(counterEncryptionLen == counterEncryption.Length);
for (var i = 0; i < des.BlockSize / 8 && offset < output.Length; ++i, ++offset)
{
output[offset] = (byte)(data[offset] ^ counterEncryption[i]);
}
}
return output;
}
}
}