Question

我正在尝试对页面进行分页，以便每页显示五种状态。输入这些代码后，它无法分页。以下是我的django应用程序中分页和更新状态的代码。

查看：

     def qask(request):
          extra_data_context={}
             #if there's nothing in the field do nothing.
          if request. method=="POST":
              form =AskForm(request.POST)
              if form.is_valid():
                  data=form.cleaned_data
                  newask=Ask(
                     user= request.user,
                     status=data['status'],
                     pub_date=datetime.datetime.now())
                 newask.save()
              extra_data_context.update({'AskForm':form})
        else:
            form = AskForm()
            extra_data_context.update({'AskForm':form})
       extra_data_context.update({'Asks':Ask.objects.filter(user=request.user)})

       plan=Ask.objects.all()
       paginator=Paginator(plan, 5)

       try:
           page=int(request.GET.get('page','1'))
       except ValueError:
           page=1

       try:
          fp=paginator.page(page)
      except (EmptyPage, InvalidPage):
          fp=paginator.page(paginator.num_pages)
      return render_to_response  ('quik_ask.html',extra_data_context,context_instance=RequestContext(request))

模板：

      {% block content %}



          {% for Ask in Asks %}
       <tr>
       <p>  {{Ask.user}} </p> </strong>
         <p>{{Ask.status}}</p>
           <p> {{Ask.pub_date|timesince }} ago </p> 

          </tr>
        {% endfor %}

    <div class="pagination">
       <span class="step-links">
    {% if Asks.has_previous %}
        <a href="?page={{ Asks.previous_page_number }}">previous</a>
    {% endif %}

    <span class="current">
        Page {{ Asks.number }} of {{ Asks.paginator.num_pages }}.
    </span>

    {% if Asks.has_next %}
        <a href="?page={{ Asks.next_page_number }}">next</a>
    {% endif %}
     </span>
</div>



 {% endblock %}

Answer 1

您的页面数据位于fp变量中，但永远不会提交给您的模板。相反，您试图从Asks获取页面数据，但它与代码中的paginator无关。我不确定你要分页的是什么，但是如果你想对你过滤的数据进行分页，它应该是这样的：

plan = Ask.objects.filter(user=request.user)
paginator=Paginator(plan, 5)
###...get you page number
try:
    asks = paginator.page(page)
except (EmptyPage, InvalidPage):
    asks = paginator.page(paginator.num_pages)
extra_data_context.update({'Asks': asks})

Django分页不起作用

1 个答案: