如何在InvokeMember
中使用方法作为参数?
我的意思是
没有反思
ContainerEvents ems = new ContainerEvents();
Test ob1 = new Test(4);
Exam ob2 = new Exam(1);
FExam ob3 = new FExam(1);
Check ob4 = new Check(5);
ems.Setplus = new Super(ob1.Write);
ems.Setplus = new Super(ob2.Write);
ems.Setplus = new Super(ob3.Write);
ems.Setplus = new Super(ob4.Write);
ems.Run();
Super是代表。
反思我想做同样的事情
Type type1 = typeof (Test);
Type type2 = typeof (Exam);
Type type3 = typeof (FExam);
Type type4 = typeof (Check);
Type events = typeof (ContainerEvents);
object eventer = Activator.CreateInstance(events);
events.InvokeMember("Setplus",BindingFlags.InvokeMethod,null,eventer,)
但我不知道要发送什么作为参数。创建Super
对象的实例?
Setplus是一个属性
public Super Setplus
{
set { obj.activate += value; }
}
obj - 类Event的对象
public class Event
{
public event Super activate ;
public void act()
{
if (activate != null) activate();
}
}
答案 0 :(得分:1)
相当于:
ContainerEvents ems = new ContainerEvents();
Test ob1 = new Test(4);
ems.Setplus = new Super(ob1.Write);
这是:
object ems = Activator.CreateInstance(typeof(ContainerEvents));
object ob1 = Activator.CreateInstance(typeof(Test), new object[] { 4 });
object super = Delegate.CreateDelegate(typeof(Super), ob1, "Write");
ems.GetType().GetProperty("SetPlus").SetValue(ems, super, null);