Java - 使用组的Reg表达式

Question

从字符串中，我需要拉出与给定模式匹配的组。

示例字符串：<XmlLrvs>FIRST</XmlLrvs><XmlLrvs>SECOND</XmlLrvs><XmlLrvs>Third</XmlLrvs>

每个小组应以<XmlLrvs>开头，以</XmlLrvs>结尾。这是我的代码片段......

String patternStr = "(<XmlLrvs>.+?</XmlLrvs>)+";

// Compile and use regular expression
Pattern pattern = Pattern.compile(patternStr);
Matcher matcher = pattern.matcher(text);
matcher.matches();

// Get all groups for this match
for (int i = 1; i<=matcher.groupCount(); i++) {
   System.out.println(matcher.group(i));
}

输出为<XmlLrvs>Third</XmlLrvs>。我期待第一组和第二组，但那些没有被捕获。有人可以帮忙吗？

Answer 1

当您应该迭代匹配时，您正在迭代组。 matches()方法检查整个输入是否匹配。你想要的是find()方法。

更改

matcher.matches();

for (int i = 1; i<=matcher.groupCount(); i++) {
    System.out.println(matcher.group(i));
}

到

while (matcher.find()) {
    System.out.println(matcher.group(1));
}

Answer 2

试一试 String patternStr = "<XmlLrvs>(.*?)</XmlLrvs>";
String text = "<XmlLrvs>FIRST</XmlLrvs><XmlLrvs>SECOND</XmlLrvs><XmlLrvs>Third</XmlLrvs>";
Pattern pattern = Pattern.compile(patternStr);


Matcher matcher = pattern.matcher(text);

while (matcher.find()) {
System.out.println(matcher.group(1));
}

The output is FIRST,SECOND,Third