我是Matlab的新手,我正在尝试将灰度图像转换为二进制图像。内置函数im2bwI(I,level)
只有一个阈值,可以使强度值低于黑色等级的所有内容都高,但是如果只有一定范围内的值变为黑色,我怎样才能做到这一点?例如,如何设置强度值为89的像素变为黑色,但值70和102变为白色?
答案 0 :(得分:2)
您可以为此使用逻辑寻址。我假设0是黑色,255是白色,你在ImageMatrix
中有你的灰度图像。请注意,白色和黑色的值取决于图像的颜色深度(6位,8位等)。
以下是代码:
%将所有89的值替换为0(黑色)。
ImageMatrix(ImageMatrix == 89) = 0;
%将所有70或102的值替换为255(白色)。
ImageMatrix(ImageMatrix == 70 | Imagematrix == 102) = 255;
使用MinValue
将MaxValue
范围内的值替换为NewValue
:
%设置一些示例值(将值替换为192 ... 255和63):
MinValue = 192;
MaxValue = 255;
NewValue = 63;
ImageMatrix(ImageMatrix >= MinValue & ImageMatrix <= MaxValue) = NewValue;
答案 1 :(得分:0)
答案: (让我成为要处理的图像)
I(I == 89) = 0
I(I == 70 | I == 102) = 255
Real MATLAB测试(R2012a):
K>> I = ceil(rand( 12 ) * 34 + 69)
I =
98 94 101 74 102 80 78 86 78 100 101 74
100 103 102 100 72 101 99 98 88 96 101 87
74 74 83 88 94 94 84 100 87 100 86 88
96 90 85 91 99 84 94 96 70 81 77 85
73 95 91 71 78 84 72 99 98 89 93 103
88 71 83 97 90 71 76 93 100 81 99 89
101 81 86 75 88 88 72 90 87 80 94 89
99 73 86 99 86 74 101 102 81 70 75 77
95 100 78 92 92 70 81 91 90 89 85 74
93 86 95 88 70 92 86 83 100 77 82 71
79 84 87 95 83 97 89 87 82 98 82 85
80 93 92 84 100 89 85 85 97 87 79 99
K>> I == 89
ans =
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 1 0 0
0 0 0 0 0 0 0 0 0 0 0 1
0 0 0 0 0 0 0 0 0 0 0 1
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 1 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 1 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0 0 0
K>> I == 70
ans =
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 1 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 1 0 0
0 0 0 0 0 1 0 0 0 0 0 0
0 0 0 0 1 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
K>> I == 102
ans =
0 0 0 0 1 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 1 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
K>> I(I == 89) = 0
I =
98 94 101 74 102 80 78 86 78 100 101 74
100 103 102 100 72 101 99 98 88 96 101 87
74 74 83 88 94 94 84 100 87 100 86 88
96 90 85 91 99 84 94 96 70 81 77 85
73 95 91 71 78 84 72 99 98 0 93 103
88 71 83 97 90 71 76 93 100 81 99 0
101 81 86 75 88 88 72 90 87 80 94 0
99 73 86 99 86 74 101 102 81 70 75 77
95 100 78 92 92 70 81 91 90 0 85 74
93 86 95 88 70 92 86 83 100 77 82 71
79 84 87 95 83 97 0 87 82 98 82 85
80 93 92 84 100 0 85 85 97 87 79 99
K>> I(I == 70 | I == 102) = 255
I =
98 94 101 74 255 80 78 86 78 100 101 74
100 103 255 100 72 101 99 98 88 96 101 87
74 74 83 88 94 94 84 100 87 100 86 88
96 90 85 91 99 84 94 96 255 81 77 85
73 95 91 71 78 84 72 99 98 0 93 103
88 71 83 97 90 71 76 93 100 81 99 0
101 81 86 75 88 88 72 90 87 80 94 0
99 73 86 99 86 74 101 255 81 255 75 77
95 100 78 92 92 255 81 91 90 0 85 74
93 86 95 88 255 92 86 83 100 77 82 71
79 84 87 95 83 97 0 87 82 98 82 85
80 93 92 84 100 0 85 85 97 87 79 99