Question

我想创建一个按钮，按下时会发送'W'，释放时发送'X'。我现在编码的方式，当我按下按钮时，它什么也没做，当我发布它时，它发送'W'。我究竟做错了什么？代码：

    but = new Button(this);
    but.setText("FORWARD");
    but.setGravity(Gravity.CENTER);
    but.setId(Tab2_Forward);
    but.setOnClickListener(this);
    but.setLayoutParams(new LayoutParams(LayoutParams.WRAP_CONTENT,
      LayoutParams.WRAP_CONTENT));
    panelH.addView(but);

    public void onClick(View v) {
       int cmdId = v.getId();
       if (cmdId == Menu_Tab1) {
          startDiscoverBluetoothDevices();
       }
       if (cmdId == Tab2_Forward) {
          if (Bee_btSocket != null)
             try {
                 Bee_btSocket.getOutputStream().write('w');
             } catch (IOException e) {
                 // TODO Auto-generated catch block
                 e.printStackTrace();
             }
          }

Answer 1

使用：

but.setOnTouchListener(btnTouch);


private View.OnTouchListener btnTouch = new View.OnTouchListener() {
    @Override
    public boolean onTouch(View v, MotionEvent event) {
        int action = event.getAction();
        if (action == MotionEvent.ACTION_DOWN)
            System.out.println("Touch");
        else if (action == MotionEvent.ACTION_UP)
            System.out.println("Release");
        return false;   //  the listener has NOT consumed the event, pass it on
    }
};

Answer 2

button.onKeyDown（）=按下时执行某些操作 and button.onKeyUp（）=在发布时执行某些操作要么 button.onTouch（）=按下时会执行某些操作 button.onClick（）=在发布时做了什么

    btn2.setOnClickListener(new View.OnClickListener() {
        public void onClick(View view) {
        makethisToastup();}});
    btn2.setOnTouchListener(new View.OnTouchListener() {
        public boolean onTouch(View view, MotionEvent event) {
        makethisToastdown();
        return false;
    }});

public void makethisToastup(){
Toast.makeText(this, "Buttonup", Toast.LENGTH_LONG).show();
}
public void makethisToastdown(){
Toast.makeText(this, "Buttondown", Toast.LENGTH_LONG).show();
}

Android中的按钮推送和按钮释放事件变得混乱

2 个答案: