我的数据库出了什么问题？

Question

我在ios项目的sqlite3数据库中创建了一个LXSGW表：

char *errorMsg; 
const char *createLXSGWSql="create table if not exists LXSGW (id integer primary key  autoincrement,name text,money_per_month integer,local_flow integer,local_pronunciation integer,local_wifi integer,past_pronunciation integer,past_flow integer,rating integer,others text )";

if (sqlite3_exec(dataBase, createLXSGWSql, NULL, NULL, &errorMsg)==SQLITE_OK) { 
    NSLog(@"create LXSGW ok."); 
}
else { 
    NSLog(@"error: %s",errorMsg); 
    sqlite3_free(errorMsg); 
}

并将两个名称为“wg001”和“wg002”的记录插入其中：

插入'wg001'：

sqlite3_stmt *stmt;

//insert records into LXSGW Table
const char *insertLXSGWSql="insert into LXSGW (name,money_per_month,local_flow,local_pronunciation,local_wifi,past_pronunciation,past_flow,rating,others) values(?,?,?,?,?,?,?,?,?)"; 

int countForLXSGW=0;              
if (sqlite3_prepare_v2(dataBase, insertLXSGWSql, -1, &stmt, nil)==SQLITE_OK) {

    sqlite3_bind_text(stmt, 1, [@"wg001" UTF8String], -1, NULL);
    sqlite3_bind_int(stmt, 2, 49);
    sqlite3_bind_int(stmt, 3,200);
    sqlite3_bind_int(stmt, 4,100);
    sqlite3_bind_int(stmt, 5, 30);
    sqlite3_bind_int(stmt, 6, 2);
    sqlite3_bind_int(stmt, 7, 3);
    sqlite3_bind_int(stmt, 8, 5);
    sqlite3_bind_text(stmt, 9, [@"其他" UTF8String], -1, NULL);

    countForLXSGW=countForLXSGW+1;           //用于计数，可以观察到数据信息插入的情况

}

if (sqlite3_step(stmt)!=SQLITE_DONE) {

    NSLog(@"insert error .....");

}
else
{
    NSLog(@"countForLXSGW is %i",countForLXSGW);
}
sqlite3_reset(stmt);

插入'wg002'：

if (sqlite3_prepare_v2(dataBase, insertLXSGWSql, -1, &stmt, nil)==SQLITE_OK) {

    sqlite3_bind_text(stmt, 1, [@"wg002" UTF8String], -1, NULL);
    sqlite3_bind_int(stmt, 2,79);
    sqlite3_bind_int(stmt, 3,200);
    sqlite3_bind_int(stmt, 4,100);
    sqlite3_bind_int(stmt, 5, 25);
    sqlite3_bind_int(stmt, 6, 2);
    sqlite3_bind_int(stmt, 7, 3);
    sqlite3_bind_int(stmt, 8, 5);
    sqlite3_bind_text(stmt, 9, [@"其他" UTF8String], -1, NULL);

    countForLXSGW=countForLXSGW+1;           //用于计数，可以观察到数据信息插入的情况

}

if (sqlite3_step(stmt)!=SQLITE_DONE) {

    NSLog(@"insert error .....");

}
else
{
    NSLog(@"countForLXSGW is %i",countForLXSGW);
}
sqlite3_reset(stmt);

还有选择代码：

//read names from LW Table For Test
//----------------------------------
const char *selectLWSql="select name from LXSGW"; 


if (sqlite3_prepare_v2(dataBase, selectLWSql, -1, &stmt, nil)==SQLITE_OK) { 

    while (sqlite3_step(stmt)==SQLITE_ROW) { 
        NSString *name=[[NSString alloc] initWithCString:(char *)sqlite3_column_text(stmt, 0) encoding:NSUTF8StringEncoding]; 
        NSLog(@"%@",name);
        [name release];
    }

}
else
{
    NSLog(@"error: %s",errorMsg); 
    sqlite3_free(errorMsg); 
}

sqlite3_reset(stmt);

当我运行项目时：