Question

我使用JSON.stringify和JQuery.ajax（）将以下JSON对象从.jsp页面传递给java servlet：

{"bin":[{"binId":"0","binDetails":[{"productCode":"AU192","qty":"4"},{"productCode":"NE823","qty":"8"}],"comments":"store pickup"},{"binId":"1","binDetails":[{"productCode":"AF634","qty":"2"}],"comments":""},{"binId":"2","binDetails":[{"productCode":"QB187","qty":"3"}],"comments":"international shipping"},{"binId":"3","binDetails":[{"productCode":"AF634","qty":"2"},{"productCode":"QB187","qty":"2"}],"comments":""}]}

这是我的java servlet中的代码：

StringBuffer strBuffer = new StringBuffer();
String line = null;

try {
   BufferedReader reader = request.getReader();
   while((line = reader.readLine()) != null){
      strBuffer.append(line);
   }
} catch (Exception e) {
}

try {
   JSONObject jsonObj = new JSONObject(new JSONTokener(strBuffer.toString()));
   // I call a method here and pass jsonObj
} catch (Exception e) {
}

在我传递jsonObj的方法中，我使用jsonObj.length（）来查找jsonObj中有多少项，它告诉我1，在这种情况下我会预期3.我甚至试过这个：< / p>

JSONObject bins = jsonObj.get("bin");
bins.length();

告诉我jsonObj.get（“bin”）不是JSONObject。在我从.jsp传递数据之前，我的数据是否格式错误，或者我在java servlet中错误地使用了JSONObject？如何访问JSONObject中的值？

Answer 1

JSONArray bins = jsonObj.getJSONArray("bin");
bins.length();

JSON数据格式

1 个答案: