Question

如果有此输入：

/Users/myMac/Desktop/MemoryAccess/BasicTest.asm/someStuff

我希望找到char "/"最后一次出现，并获取字符串BasicTest

这样做的好方法是什么？

谢谢！

Answer 1

os.path模块提供基本的路径名操作。

>>> from os.path import *
>>> file = '/Users/myMac/Desktop/MemoryAccess/BasicTest.asm/someStuff'
>>> splitext(basename(dirname(file)))[0]
'BasicTest'

Answer 2

>>> s = "/Users/myMac/Desktop/MemoryAccess/BasicTest.asm/someStuff"
>>> ind = s.rfind('/')
>>> ind1 = s[:ind].rfind('/')
>>> print(s[ind1+1:ind].split('.')[0])
BasicTest

Answer 3

这是os的一个例子：

>>> p = '/Users/myMac/Desktop/MemoryAccess/BasicTest.asm/someStuff'
>>> os.path.dirname(p)
'/Users/myMac/Desktop/MemoryAccess/BasicTest.asm'
>>> os.path.splitext(os.path.dirname(p))
('/Users/myMac/Desktop/MemoryAccess/BasicTest', '.asm')
>>> os.path.basename(os.path.splitext(os.path.dirname(p))[0])
'BasicTest'

Answer 4

好吧，“BasicTest”遵循“/”的倒数第二次出现，但除此之外，请尝试rfind。

Answer 5

以下将返回BasicTest.asm，这是战斗的一半：

'/Users/myMac/Desktop/MemoryAccess/BasicTest.asm/someStuff'.split('/')[-2]

可以使用相同的技巧拆分'。'

'BasicTest.asm'.split('.')[0]

Answer 6

使用re in python

import re
s = "/Users/myMac/Desktop/MemoryAccess/BasicTest.asm/someStuff"
pattern = re.compile(r"/(\w+)\.\w+/\w*$")
match = re.search(pattern,s)
print match.group(1)

在字符串中查找最后一个char外观

6 个答案: