使用http.send（）ajax

Question

if(document.getElementById(callerName).checked) {
    //alert(callerName);        
    var poststr = "field=" + escape(encodeURI(callerName)) +
      "&op=add" + "&nocache=" + nocache;
}
else {
    //alert(callerName);
    var poststr = "field=" + escape(encodeURI(callerName)) + 
      "&op=del" + "&nocache=" + nocache;
}
http.send(poststr);

当我收到$_POST['field']我得到的'％20'有空格时，有什么解决方案可以获得确切的字符串吗？

Answer 1

PHP：

$field = urldecode($_POST['field']);

Answer 2

您同时使用escape和encodeURI双重转发数据。另外，我建议您改用encodeURIComponent。尝试改为：

var poststr = "field=" + encodeURIComponent(callerName) + 
  "&op=add&nocache=" + nocache;