我有一个包含事件的表,列出这些事件我循环遍历事件表,检查事件类型并在它的特定表中查找它的值,并使用它的eventId。
目前,这使用一个查询来获取20个事件,然后使用最多3个查询来获取这些事件的数据。我目前在程序上编码,但需要更改它,以便最后它只返回数组形式的数据。
这是我需要实现的Pseduo代码示例:
while(eventQuery):
if commentQueryResult;
$array .= commentQueryResult;
if forumPostQueryResult;
$array .= forumPostQueryResult;
if uploadItemQueryResult;
$array .= uploadItemQueryResult;
endwhile;
return $array; // Combined returned results as one array
然后我将能够访问数据,并且只是通过它循环。
我只是不确定将多个结果集合并到数组中的最佳方法?
或者你可以尝试将它们组合成一个查询...
$eventResult = mysql_query(
'SELECT userevent.event, userevent.eventId, userevent.friendId
FROM userevent
WHERE userevent.userId = 1 OR userevent.friendId = 1
ORDER BY userevent.id DESC
LIMIT 20'
);
while ($eventRow = mysql_fetch_row($eventResult)){
if($eventRow[0] == 1){
$result = mysql_fetch_array(mysql_query("
SELECT forumRooms.id, forumRooms.title
FROM forumPosts
INNER JOIN forumRooms ON forumPosts.`forumTopic` = forumRooms.`id`
WHERE forumPosts.id = '$eventRow[1]'"));
}
elseif($eventRow[0] == 2){
$result = mysql_fetch_array(mysql_query("
SELECT game.id, game.uriTitle, game.title
FROM usergamecomment
INNER JOIN game ON usergamecomment.`gameId` = game.id
WHERE usergamecomment.id = $eventRow[1]"));
}
elseif($eventRow[0] == 4){
$result = mysql_fetch_array(mysql_query("
SELECT usercomment.comment, UNIX_TIMESTAMP(usercomment.TIME), `user`.id, `user`.username, `user`.activate
FROM usercomment
INNER JOIN `user` ON usercomment.`userId` = `user`.id
WHERE usercomment.id = $eventRow[1]
AND `user`.activate = 1"));
}
elseif($eventRow[0] == 5){
$result = mysql_fetch_array(mysql_query("
SELECT game.id, game.title, game.uriTitle
FROM game
WHERE game.id = $eventRow[1]"));
}
// Combined Results as array
}
我正在将所有这些转换为PDO,这是在确定最小化此方法的最佳方法之后的下一步。
答案 0 :(得分:1)
接受挑战。 ;)
由于您实际上只对while循环中的结果感兴趣,因此您可以尝试此单个查询。由于LEFT JOINS它可能不会更快,几乎取决于您的数据库。最终$result
包含所有元素及其各自的字段。
$result = array();
$q = 'SELECT userevent.event AS userevent_event,
userevent.eventId AS userevent_eventId,
userevent.friendId AS userevent_friendId,
forumRooms.id AS forumRooms_id,
forumRooms.title AS forumRooms_title,
game.id AS game_id,
game.uriTitle AS game_uriTitle,
game.title AS game_title,
usercomment.comment AS usercomment_comment,
UNIX_TIMESTAMP(usercomment.TIME) AS usercomment_time,
user.id AS user_id,
user.username AS user_username,
user.activate AS user_activate,
g2.id AS game2_id,
g2.uriTitle AS game2_uriTitle,
g2.title AS game2_title
FROM userevent
LEFT JOIN forumPosts ON forumPosts.id = userevent.eventId
LEFT JOIN forumRooms ON forumPosts.forumTopic = forumRooms.id
LEFT JOIN usergamecomment ON usergamecomment.id = userevent.eventId
LEFT JOIN game ON usergamecomment.gameId = game.id
LEFT JOIN usercomment ON usercomment.id = userevent.eventId
LEFT JOIN user ON usercomment.userId = user.id
LEFT JOIN game g2 ON userevent.eventId = g2.id
WHERE (userevent.userId = 1 OR userevent.friendId = 1)
AND userevent.eventId >= (SELECT userevent.eventId
WHERE userevent.userId = 1 OR userevent.friendId = 1
ORDER BY userevent.id DESC LIMIT 1,20);';
$r = mysql_query($q);
while ( $o = mysql_fetch_row($r) ) {
switch($o['userevent_event']) {
case 1:
$result[] = array(
'id' => $o['forumsRooms_id'],
'title' => $o['forumsRooms_title'],
);
break;
case 2:
$result[] = array(
'id' => $o['game_id'],
'uriTitle' => $o['game_uriTitle'],
'title' => $o['game_title'],
);
break;
case 4:
$result[] = array(
'comment' => $o['usercomment_comment'],
'time' => $o['usercomment_time'],
'id' => $o['user_id'],
'username' => $o['user_username'],
'activate' => $o['user_activate'],
);
break;
case 5:
$result[] = array(
'id' => $o['game2_id'],
'uriTitle' => $o['game2_uriTitle'],
'title' => $o['game2_title'],
);
break;
}
}
注意:最终,查询必须稍微进行编辑,我只是在脑海中编写了w / o测试。如果我对db结构有更多了解,肯定可以进行优化。
此外,这仅仅是一个概念证明,它确实可以通过单个查询来完成。 ;)强> 的