我知道有无数线程提出这个问题,但我找不到能帮助我解决这个问题的线索。
我基本上是在尝试解析大约10,000,000个URL的列表,确保它们符合以下条件,然后获取根域URL。此列表包含您可以想象的所有内容,包括(和预期的格式化URL)之类的内容:
biy.ly/test [VALID] [return - bit.ly]
example.com/apples?test=1&id=4 [VALID] [return - example.com]
host101.wow404.apples.test.com/cert/blah [VALID] [return - test.com]
101.121.44.xxx [**inVALID**] [return false]
localhost/noway [**inVALID**] [return false]
www.awesome.com [VALID] [return - awesome.com]
i am so awesome [**inVALID**] [return false]
http://404.mynewsite.com/visits/page/view/1/ [VALID] [return - mynewsite.com]
www1.151.com/searchresults [VALID] [return - 151.com]
有人对此有任何建议吗?
答案 0 :(得分:14)
^(?:https?://)?(?:[a-z0-9-]+\.)*((?:[a-z0-9-]+\.)[a-z]+)
解释
^ # start-of-line
(?: # begin non-capturing group
https? # "http" or "https"
:// # "://"
)? # end non-capturing group, make optional
(?: # start non-capturing group
[a-z0-9-]+\. # a name part (numbers, ASCII letters, dashes) & a dot
)* # end non-capturing group, match as often as possible
( # begin group 1 (this will be the domain name)
(?: # start non-capturing group
[a-z0-9-]+\. # a name part, same as above
) # end non-capturing group
[a-z]+ # the TLD
) # end group 1
答案 1 :(得分:2)
我会从默认开始:
filter_var($inputUrl, FILTER_VALIDATE_URL);
然后添加您无法接受进一步验证的特殊情况。这应该简化一下。
至于获得主持人。
parse_url($inputUrl, PHP_URL_HOST);
答案 2 :(得分:0)
^(([a-zA-Z](\.[a-zA-Z])+)|([0-9]{1,3}(\.[0-9]{1,3}){3})/.*$
修改强>
在php中preg_match ( '^(([a-zA-Z](\.[a-zA-Z])+)|([0-9]{1,3}(\.[0-9]{1,3}){3})/.*$' , $myUrls , $matches)
您需要的是$matches[1]
答案 3 :(得分:0)
$website = test_input($_POST["website"]);
if (!preg_match("/\b(?:(?:https?|ftp):\/\/|www\.)[-a-z0-9+&@#\/%?=~_|!:,.;]*[-a-z0-9+&@#\/%=~_|]/i",$w$website = test_input($_POST["website"]);
if (!preg_match("/\b(?:(?:https?|ftp):\/\/|www\.)[-a-z0-9+&@#\/%?=~_|!:,.;]*[-a-z0-9+&@#\/%=~_|]/i",$website))
{
$websiteErr = "Invalid URL";
}ebsite))
{
$websiteErr = "Invalid URL";
}