Question

我坚持这种愚蠢的形式......继承我的代码。它将它保存在streamwriter想要的地方，但当我通过savedialog框保存到用户想要的地方时，它会创建XML，但不会放入任何内容！有人可以看看，因为它开始让我振作起来！

void SavebuttonClick(object sender, EventArgs e)
{
    Stream myStream ;
    SaveFileDialog savefile1 = new SaveFileDialog();

    savefile1.Filter = "xml files |*.xml"  ;
    savefile1.FilterIndex = 2 ;
    savefile1.RestoreDirectory = true ;

    if(savefile1.ShowDialog() == DialogResult.OK)
    {
        if((myStream = savefile1.OpenFile()) != null)
        {
            Values v = new Values();
            v.task1_name = this.task1_name.Text;
            v.task1_desc = this.task1_desc.Text;
            v.task1_date = this.task1_date.Value;
            v.task1_time = this.task1_time.Value;
            SaveValues(v);
        }
        myStream.Close();   
    }
}

这是节选者......

public void SaveValues(Values v)
{
    XmlSerializer serializer = new XmlSerializer(typeof(Values));
    using(TextWriter textWriter = new StreamWriter(@"E:\TheFileYouWantToStore.xml"))
    {
        serializer.Serialize(textWriter, v);
    }
...
}

编辑：

public class Values 
{
public string task1_name { get; set;}
public string task1_desc { get; set;}
public DateTime task1_date { get; set;}
public DateTime task1_time { get; set;}
}

我认为这是你所说的代码，虽然对于编码虽然相当新：但是

Answer 1

序列化后您必须致电textWriter.close();。如果你不关闭编写器，它将不会将chenges应用于文件。顺便说一句，您要将值写入 E：\ TheFileYouWantToStore.xml 。您的保存保存方法不使用用户文件。

public void SaveValues(Values v)
{
    XmlSerializer serializer = new XmlSerializer(typeof(Values));
    using(TextWriter textWriter = new StreamWriter(@"E:\TheFileYouWantToStore.xml"))
    {
        serializer.Serialize(textWriter, v);
        textWriter.close();
    }
...
}

修改

if(savefile1.ShowDialog() == DialogResult.OK) { Values v = new Values(); v.task1_name = this.task1_name.Text; v.task1_desc = this.task1_desc.Text; v.task1_date = this.task1_date.Value; v.task1_time = this.task1_time.Value; SaveValues(savefile1.FileName, v); }

-

public void SaveValues(string fileName, Values v) { XmlSerializer serializer = new XmlSerializer(typeof(Values)); using(TextWriter textWriter = new StreamWriter(fileName)) { serializer.Serialize(textWriter, v); textWriter.close(); } ... }

Windows窗体XML序列化保存对话框

1 个答案: