Question

我有以下字符串“Class（102）（401）”和“Class（401）”我想找到正则表达式来查找子字符串总是返回我的最后一个括号值，在我的情况下它是'（401）'

以下是我的代码

Pattern MY_PATTERN = Pattern.compile(".*(\\(\\d+\\))");
    Matcher mat = MY_PATTERN.matcher("Class (102) (401)");
    while (mat.find()){
        System.out.println(mat.group());
    }

它正在返回

- （ - ） - （ - ）

Answer 1

您可以使用：

Pattern MY_PATTERN = Pattern.compile(".*(\\(\\d+\\))");

See it

Answer 2

试试这个：

(?<=\()[^\)(]+(?=\)[^\)\(]+$)

<强>解释

<!--
(?<=\()[^\)(]+(?=\)[^\)\(]+$)

Options: ^ and $ match at line breaks; free-spacing

Assert that the regex below can be matched, with the match ending at this position (positive lookbehind) «(?<=\()»
   Match the character “(” literally «\(»
Match a single character NOT present in the list below «[^\)(]+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
   A ) character «\)»
   The character “(” «(»
Assert that the regex below can be matched, starting at this position (positive lookahead) «(?=\)[^\)\(]+$)»
   Match the character “)” literally «\)»
   Match a single character NOT present in the list below «[^\)\(]+»
      Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
      A ) character «\)»
      A ( character «\(»
   Assert position at the end of a line (at the end of the string or before a line break character) «$»
-->

Answer 3

表达式如何：.*\$([^\\(\$]+)\\)[^\$\$]*$

它找到一个(后面跟着非括号[^\$\$]（你想要的字符串）后跟一个)，之后只允许非括号，所以它必须是最后一个

Java Regex查找子字符串

3 个答案: