Question

我通过按组件分隔字符串来创建一个nsmutable数组，这会导致在数组中插入大量新的行和空格以便如何识别和删除它们？

for (int i=0;i<contentsOfFile.count; i++) 
 {
        if(!([[contentsOfFile objectAtIndex:i]isEqual:@"\n"]||[[contentsOfFile     objectAtIndex:i]isEqual:@""]))
       [arrayToBereturned addObject:[contentsOfFile objectAtIndex:i]];
 }

我正在使用的这段代码无法识别所有新的线路查找器感谢

Answer 1

删除字符串中的所有额外空格和\ n -

NSString* result = [yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];

而不是准备你的contentsOfFile数组。

Answer 2

如果你想要一个没有空格的数组：

NSString *string = @"Hello, World!";
NSCharacterSet *separator = [NSCharacterSet whitespaceAndNewlineCharacterSet];
NSArray *stringComponents = [string componentsSeparatedByCharactersInSet:separator];

Answer 3

stringByTrimmingCharachersInSet:仅从字符串的结尾和开头删除所需的字符。要删除所有出现，请使用stringByReplacingOccurrencesOfString:

Answer 4

Swift 5版本

    let string = "Hello, stack overflow!"
    let components = string.components(separatedBy: .whitespacesAndNewlines)
    print(components) // prints ["Hello,", "stack", "overflow!"]

还涉及string.replacingOccurrences

    let string = " Hello, stack overflow     ! "
    let noSpacingsString = string.replacingOccurrences(of: " ", with: "")
    print(components) // prints "Hello,stackoverflow!"

如何识别和删除换行符和空格？

4 个答案: