RSpec和Factory Girl的新手,并且放弃了这场战斗!
我有一个连接表MealItems,它对其中一个属性进行了验证。在rails控制台中,我可以成功执行以下操作:
meal = Meal.create!( ... )
food = Food.create!( ... )
item1 = MealItem.create!( meal, food, 1234 ) # 1234 being the property that is required
然后,我可以通过MealItem自动获取给定膳食中的一系列食物,如下所示:
meal.foods
问题在于我无法弄清楚如何正确创建工厂,因此规范中提供了这种关系。我可以把这些物品分配给一顿饭,然后测试一下,但是不能通过关系工作得到has_many(meal.foods)
模型
class Meal < ActiveRecord::Base
has_many :meal_items
has_many :foods, :through => :meal_items
end
class MealItem < ActiveRecord::Base
belongs_to :meal
belongs_to :food
validates_numericality_of :serving_size, :presence => true,
:greater_than => 0
end
class Food < ActiveRecord::Base
has_many :meal_items
has_many :meals, :through => :meal_items
end
规格/ factories.rb
FactoryGirl.define do
factory :lunch, class: Meal do
name "Lunch"
eaten_at Time.now
end
factory :chicken, class: Food do
name "Western Family Bonless Chicken Breast"
serving_size 100
calories 100
fat 2.5
carbohydrates 0
protein 19
end
factory :cheese, class: Food do
name "Armstrong Light Cheddar"
serving_size 30
calories 90
fat 6
carbohydrates 0
protein 8
end
factory :bread, class: Food do
name "'The Big 16' Multigrain Bread"
serving_size 38
calories 100
fat 1
carbohydrates 17
protein 6
end
factory :item1, class: MealItem do
serving_size 100
association :meal, factory: :lunch
association :food, factory: :chicken
end
factory :item2, class: MealItem do
serving_size 15
association :meal, factory: :lunch
association :food, factory: :cheese
end
factory :item3, class: MealItem do
serving_size 76
association :food, factory: :bread
association :meal, factory: :lunch
end
factory :meal_with_foods, :parent => :lunch do |lunch|
lunch.meal_items { |food| [ food.association(:item1),
food.association(:item2),
food.association(:item3)
]}
end
end
规格/模型/ meal_spec.rb
...
describe "Nutritional Information" do
before(:each) do
#@lunch = FactoryGirl.create(:meal_with_foods)
@item1 = FactoryGirl.create(:item1)
@item2 = FactoryGirl.create(:item2)
@item3 = FactoryGirl.create(:item3)
@meal = FactoryGirl.create(:lunch)
@meal.meal_items << @item1
@meal.meal_items << @item2
@meal.meal_items << @item3
@total_cals = BigDecimal('345')
@total_fat = BigDecimal('7.5')
@total_carbs = BigDecimal('34')
@total_protein = BigDecimal('35')
end
# Would really like to have
#it "should have the right foods through meal_items" do
#@meal.foods[0].should == @item1.food
#end
it "should have the right foods through meal_items" do
@meal.meal_items[0].food.should == @item1.food
end
it "should have the right amount of calories" do
@meal.calories.should == @total_cals
end
...
我的问题是:
我如何设置这些工厂,以便我可以在测试中引用Meal.foods,因为我不能直接将食物分配给餐,因为连接表上的验证要求。我在测试期间没有正确地将MealItem工厂写入数据库,这就是为什么我的规范中不存在has_many through关系?
非常感谢任何帮助。
答案 0 :(得分:0)
是的,您需要MealItem的工厂,并且您需要在规范中使用该工厂才能通过验证。如果除了两个外键之外没有任何必填字段,它可能已经有效了。 因此,在使用默认服务器大小设置工厂后,您将替换它:
@meal.meal_items << @item1
@meal.meal_items << @item2
@meal.meal_items << @item3
用这个:
FactoryGirl.create(:meal_item, :meal => @meal, :item => @item1)
FactoryGirl.create(:meal_item, :meal => @meal, :item => @item1)
FactoryGirl.create(:meal_item, :meal => @meal, :item => @item1)
另一种方法是在模型中设置默认的服务大小。这样您就可以按原样保留测试,并且可以更容易在实际代码中使用首选语法。