考虑下表:
+---------+---------+------------+----------+------------+
| msg_id | user_id | _date | _time | count_for |
+-------------------+------------+----------+------------+
| 1 | 1 | 2011-01-22 | 06:23:11 | 2011-01-22 |
| 2 | 1 | 2011-01-23 | 16:17:03 | 2011-01-24 |
| 3 | 1 | 2011-01-23 | 17:05:45 | 2011-01-24 |
| 4 | 2 | 2011-01-24 | 06:58:13 | 2011-01-24 |
| 5 | 2 | 2011-01-24 | 15:59:32 | 2011-01-24 |
| 6 | 3 | 2011-01-25 | 13:45:00 | ... |
| 7 | 3 | 2011-01-26 | 13:22:34 | ... |
+---------+---------+------------+----------+------------+
我想计算每天的邮件数量,但是今天16:00之后的邮件必须计入第二天:
- msg 1在2011-01-22
的16:00之前写入,因此count_for是(同一天)2011-01-22
- msg 2在2011-01-23
的16:00之后写入,因此count_for是(第二天)2011-01-24
显然,我手动完成了前5个。我的问题是:我可以使用什么查询自动执行此操作(在MySQL中)?
答案 0 :(得分:2)
像
这样的东西SELECT count(msg_id), if(_time >= '16:00:00', _date + INTERVAL 1 DAY, _date) AS effective_date
FROM yourtable
GROUP BY effective_date
应该这样做。
答案 1 :(得分:1)
SELECT IF(_time < '16:00:00', _date, ADDDATE(_date, 1)) AS d, COUNT(*)
FROM `table`
GROUP BY d