Question

我收到的结果：

id   sku           name                                                              GROUP_CONCAT(quantity_received)                                                                                                            GROUP_CONCAT(item_cost)                                      
4   00004   Antibacterial Wipes     50,14,25,309,50,14,25,309,50,14,25,309,50,14,25,309,50,14,25,309,50,14,25,309,50,14,25,309,50,14,25,309,50,14,25,309    3.29,3.29,3.29,3.49,3.29,3.29,3.29,3.49,3.29,3.29,3.29,3.49,3.29,3.29,3.29,3.49,3.29,3.29,3.29,3.49,3.29,3.29,3.29,3.49,3.29,3.29,3.29,3.49,3.29,3.29,3.29,3.49,3.29,3.29,3.29,3.49

我想要的结果：

id   sku            name        GROUP_CONCAT(DISTINCT quantity_received)    GROUP_CONCAT(DISTINCT item_cost)
4   00004   Antibacterial Wipes             50,14,25,309                            3.29,3.49

我解决此问题的方法是将DISTINCT放入quantity_recieved选择中。问题是，如果数量有两个相同的值，如50,50,14,25。结果将是50,14,25。我只是想摆脱重复的数字，只得到一次值。

以下是查询：

SELECT `product`.`id`,`product`.`sku`,`product`.`name`,
    case when coalesce(stock1.`quantity`, '') = '' 
        then '0' 
        else stock1.`quantity` 
    end as qty_warehouse,
    case when coalesce(sum(distinct stock2.`quantity`), '') = '' 
        then '0' 
        else sum(distinct stock2.`quantity`) 
    end as qty_events,
    case when coalesce(stock1.`quantity`, '') = '' 
        then '0' 
        else stock1.`quantity` 
    end + 
    case when coalesce(sum(distinct stock2.`quantity`), '') = '' 
        then '0' 
        else sum(distinct stock2.`quantity`) 
    end as qty_total
GROUP_CONCAT(DISTINCT quantity_received) ,
GROUP_CONCAT(DISTINCT item_cost)
FROM (`product`)
LEFT JOIN`shipping_event` 
    ON `shipping_event`.`product_id` = `product`.`id`
LEFT JOIN `product_stock` as stock1 
    ON `product`.`id` = `stock1`.`product_id` and `stock1`.`location_id` = 112 
LEFT JOIN `product_stock` as stock2 
    ON `product`.`id` = `stock2`.`product_id` and `stock2`.`location_id` != 112  
LEFT JOIN `shipping_list` 
    ON `shipping_event`.`shipping_list_id` = `shipping_list`.`id` 
WHERE `shipping_list`.`type` = 'incoming' 
    AND `shipping_event`.`end_date` > '2004-01-01 01:01:01' 
GROUP BY `product`.`id` 
ORDER BY `sku` asc LIMIT 20

我正在使用group concat来显示这种情况下的结果。我实际上将quantity_received相加，然后按项目成本加倍。

Answer 1

您可以使用GROUP BY然后JOIN创建一个子查询到product表。

同样的逻辑也可以应用于其他连接表。如果您这样做，可以跳过GROUP BY product.id：

SELECT p.id
     , p.sku
     , p.name
     , COALESCE(stock1.quantity, 0)                  --- minor improvements on
         AS qty_warehouse                            --- the long CASE clauses
     , COALESCE(SUM(DISTINCT stock2.quantity), 0) 
         AS qty_events
     , COALESCE(stock1.quantity, 0) + COALESCE(SUM(DISTINCT stock2.quantity), 0)
         AS qty_total
     , grp.all_quantities_received
     , grp.all_item_costs
FROM product AS p
  LEFT JOIN 
      ( SELECT product_id
             , GROUP_CONCAT(se.quantity_received) AS all_quantities_received
             , GROUP_CONCAT(se.item_cost)         AS all_item_costs
        FROM shipping_event AS se
          LEFT JOIN shipping_list AS sl
            ON  se.shipping_list_id = sl.id 
        WHERE sl.type = 'incoming' 
          AND se.end_date > '2004-01-01 01:01:01' 
        GROUP BY se.product_id
      ) AS grp
    ON  grp.product_id = p.id
  LEFT JOIN `product_stock` AS stock1 
    ON  p.id = stock1.product_id 
    AND stock1.location_id = 112 
  LEFT JOIN product_stock AS stock2 
    ON  p.id = stock2.product_id 
    AND stock2.location_id <> 112  
GROUP BY p.id 
ORDER BY sku ASC
LIMIT 20

Left Joins返回重复值

1 个答案: