将结果与DateDiff组合在一起

Question

我列出了人们已经出院的地方，我需要按年龄对他们进行分层。我目前在下面的查询工作，但它列出了每个年龄的每个排放类型计数。

你可以看到0-1-2-3岁如何根据年龄分别计算排出类型。如何才能使它只有dischargeType和列出的计数（只要它们是18及以下）

SELECT DATEDIFF(yyyy, tblVisits.dob, tblVisits.admitdate) AS Age, tblDischarge.dischargeType, COUNT(tblDischarge.dischargeType) AS COUNTS
FROM tblVisits INNER JOIN
               tblDischarge ON tblVisitsDischargeStatus = tblDischarge.dis_statID
GROUP BY DATEDIFF(yyyy,tblVisits.dob, tblVisits.Admitdate), tblDischarge.dischargeType
HAVING (DATEDIFF(yyyy,tblVisits.DOB, tblVisits.AdmitDate) <=18)

Answer 1

如果你只是想要18岁以下的人，但每个出院型只有一排......

SELECT
  tblDischarge.dischargeType,
  COUNT(tblDischarge.dischargeType) AS COUNTS
FROM
  tblVisits
INNER JOIN
  tblDischarge
    ON tblVisitsDischargeStatus = tblDischarge.dis_statID
WHERE
  (DATEDIFF(yyyy,tblVisits.DOB, tblVisits.AdmitDate) <=18) 
GROUP BY
  tblDischarge.dischargeType

如果你想把年龄分组到分层......

SELECT
  tblDischarge.dischargeType,
  CASE DATEDIFF(yyyy,tblVisits.DOB, tblVisits.AdmitDate)
     WHEN <=  3 THEN '0..3'
     WHEN <=  8 THEN '4..8'
     WHEN <= 12 THEN '9..12'
                ELSE '13..18'
  END                               AS ageBand,
  COUNT(tblDischarge.dischargeType) AS COUNTS
FROM
  tblVisits
INNER JOIN
  tblDischarge
    ON tblVisitsDischargeStatus = tblDischarge.dis_statID
WHERE
  (DATEDIFF(yyyy,tblVisits.DOB, tblVisits.AdmitDate) <=18)
GROUP BY
  tblDischarge.dischargeType,
  CASE DATEDIFF(yyyy,tblVisits.DOB, tblVisits.AdmitDate)
     WHEN <=  3 THEN '0..3'
     WHEN <=  8 THEN '4..8'
     WHEN <= 12 THEN '9..12'
                ELSE '13..18'
  END

Answer 2

我不确定您的问题，但如果您只想按dischargeType计算，对于所有18岁以下的人，代码如下：

SELECT dis.dischargeType, COUNT(dis.dischargeType) AS COUNTS
FROM tblDischarge dis
JOIN tblVisits    vst ON vst.DischargeStatus = dis.dis_statID
WHERE (DATEDIFF(yyyy,vst.DOB, vst.AdmitDate) <= 18)
GROUP BY dis.dischargeType;

或者您可以使用子查询，例如：

SELECT dischargeType, COUNT(dischargeType) AS COUNTS
FROM tblDischarge
WHERE dis_statID IN (
    SELECT vst.DischargeStatus
    FROM tblVisits vst
    WHERE (DATEDIFF(yyyy, vst.DOB, vst.AdmitDate) <= 18)
)
GROUP BY dis.dischargeType;

Answer 3

删除选择中的AGE和按部分分组：

SELECT tblDischarge.dischargeType, COUNT(tblDischarge.dischargeType) AS COUNTS
FROM tblVisits INNER JOIN
               tblDischarge ON tblVisitsDischargeStatus = tblDischarge.dis_statID
GROUP BY tblDischarge.dischargeType
HAVING (DATEDIFF(yyyy,tblVisits.DOB, tblVisits.AdmitDate) <=18)

Answer 4

只需从SELECT和GROUP BY中移除年龄计算，然后将HAVING更改为WHERE：

SELECT tblDischarge.dischargeType,
        COUNT(tblDischarge.dischargeType) as COUNTS
FROM tblVisits 
INNER JOIN tblDischarge
  ON tblVisitsDischargeStatus = tblDischarge.dis_statID
WHERE (DATEDIFF(yyyy,tblVisits.DOB, tblVisits.AdmitDate) <=18) 
GROUP BY tblDischarge.dischargeType