Question

array=('org.battery.plist' 'org.disk.plist' 'org.memory.plist');

echo "1) org.battery.plist"
echo "2) org.disk.plist"
echo "3) org.memory.plist"

echo "Enter selection(s) to load, separated by commas: "
read var

sudo launchctl load -w ${array[$var]}

我是否在正确的轨道上？我有点卡住了。有人可以帮忙吗？

如果用户输入1,2，我希望脚本在下面执行此操作 -

sudo launchctl load -w org.disk.plist
sudo launchctl load -w org.memory.plist

Answer 1

试试这个，

IFS=","
for i in $var
do
    sudo launchctl load -w ${array[$i - 1]}
done

您还需要检查输入是否超出数组范围，抛出和错误。

Answer 2

bash中有一个建筑用于这样的选择，令人惊讶的是，称为“选择”：

select entry in ${array[@]}; 
do  
    sudo launchctl load -w $entry
done

试试help select。

Answer 3

这样更好：

array=('org.battery.plist' 'org.disk.plist' 'org.memory.plist');

for (( i=0;i<"${#array[@]}";i++ )) ; do
    let n=i+1
    printf '%d) %s\n' $n "${array[$i]}"
done

IFS=, read -r -p 'Enter selection(s) to load, separated by commas: ' -a selections

for selection in "${selections[@]}" ; do
    let selection=selection-1
    sudo launchctl load -w "${array[$selection]}"
done

bash脚本数组

3 个答案: