我正在写一个照片程序,它接受用户的互联网速度,照片的宽度和高度。然后程序显示成本,存储大小和传输时间。我将程序分为两部分,一部分设置值,另一部分包含所有方法。
我对我的程序的主要问题是将所有输入的照片的所有值加起来,并在最后显示价格,存储空间和时间。
到目前为止,我有一个addTotal()方法,它将时间,价格和存储空间添加到我设置的值中。不断发生的是,输入的最后一张照片的值保持显示而不是所有照片的总和。
例如: 如果互联网速度设置为150,000,并且有两张尺寸为4,5和4.5,4.5的照片,最后显示的是:
总费用= $ 4.83
4.14 MB的存储空间
3分40秒转移
感谢任何帮助。
这是主程序:
import javax.swing.JOptionPane;
{
public static void main(String args[])
{
double speed;
double height;
double width;
double compression = 3.5;
double resolution = 600;
System.out.println("Welcome to the Scans-R-Us Digital Photo Shop!");
String userInput = JOptionPane.showInputDialog("Do you have a photo you would like us to scan(Yes or No)?");
while((!userInput.equals("Yes") && (!userInput.equals("YES")) && (!userInput.equals("yes"))))
{
System.out.println("test");
System.exit(0);
}
do
{
String internetString = JOptionPane.showInputDialog("What is your internet speed in bits/second?");
speed = Double.parseDouble(internetString);
}
while(speed < 0);
while((userInput.compareTo("No") != 0) && (userInput.compareTo("NO") != 0) && (userInput.compareTo("no") != 0))
{
DigitalPhoto one = new DigitalPhoto();
do
{
String heightString = JOptionPane.showInputDialog("What is the height of the photo?");
height = Double.parseDouble(heightString);
}
while(height >=8);
do
{
String widthString = JOptionPane.showInputDialog("What is the width of the photo?");
width = Double.parseDouble(widthString);
}
while(width >= 8);
one.setWidth(width);
one.setHeight(height);
one.setSpeed(speed);
one.setCompression(compression);
one.setResolution(resolution);
one.setPrice();
one.setStorage();
one.setTime();
one.showValues();
one.addTotal();
userInput = JOptionPane.showInputDialog("Do you have a photo you would like us to scan(Yes or No)?");
while((!userInput.equals("Yes") && (!userInput.equals("YES")) && (!userInput.equals("yes"))))
{
one.endValues();
System.out.println("\nThanks, have a nice day!");
System.exit(0);
}
}
}
}
这是我用来运行程序的类:
import javax.swing.JOptionPane;
{
double total;
double width;
double height;
double speed;
double compression;
double resolution;
double price;
double time;
double totalPrice;
double totalStorage;
double totalTime;
double pricePerInch = .12;
int bytes = 8;
int megaSize = 1000000;
DigitalPhoto()
{
width = 0.0;
height = 0.0;
speed = 0.0;
compression = 0.0;
resolution = 0.0;
total = 0.0;
price = 0.0;
time = 0.0;
}
public void setWidth(double thisWidth)
{
width = thisWidth;
}
public void setHeight(double thisHeight)
{
height = thisHeight;
}
public void setSpeed(double thisSpeed)
{
speed = thisSpeed;
}
public void setCompression(double thisCompression)
{
compression = thisCompression;
}
public void setResolution(double thisResolution)
{
resolution = thisResolution;
}
public double getWidth()
{
return width;
}
public double getHeight()
{
return height;
}
public double getSpeed()
{
return speed;
}
public double getCompression()
{
return compression;
}
public double getResolution()
{
return resolution;
}
public double setStorage()
{
width = width * resolution;
height = height * resolution;
total = width * height;
total = total / compression;
total = total / megaSize;
return total;
}
public double setPrice()
{
price = height * width;
price = price * pricePerInch;
return price;
}
public double setTime()
{
total = total * megaSize;
time = total * bytes;
time = time / speed;
total = total / megaSize;
return time;
}
public void showValues()
{
System.out.println("\nScanned photo details: ");
System.out.println("Resolution: " + resolution);
System.out.println("Compression ratio: " + compression);
System.out.println("The customer photos require " + total + " Mbytes of storage.");
System.out.println("The customer photos cost $" + price);
System.out.println("It will take " + (int)time / 60 + " minutes and " + (int)time % 60 + " seconds");
}
public void addTotal()
{
totalTime = totalTime + time;
totalPrice = totalPrice + price;
totalStorage = totalStorage + total;
}
public void endValues()
{
System.out.println("\nThe photos require " + totalStorage + " Mbytes of storage.");
System.out.println("The photos cost $" + totalPrice);
System.out.println("It will take " + (int)totalTime / 60 + " minutes and " + (int)totalTime % 60 + " seconds");
}
}
答案 0 :(得分:1)
每次进入循环时都在创建一个新对象,所以你只保留最后一个。您需要在循环之前创建对象:
DigitalPhoto one = new DigitalPhoto();
while((userInput.compareTo("No") != 0) && (userInput.compareTo("NO") != 0) &&
(userInput.compareTo("no") != 0)) {
//...
one.setPrice();
//...
one.addTotal();
}
然后在循环结束后查询结果。