Question

我有来自flikr的RSS源

http://api.flickr.com/services/feeds/photoset.gne?set=72157629920039099&nsid=50910794@N07&lang=en-us&format=rss_200

在这里有一个媒体：description，media：thumbnail e.t.c

我正在努力从媒体上获取网址：缩略图，但我没有运气！

我的代码......

$content = file_get_contents("http://api.flickr.com/services/feeds/photoset.gne?set=72157629920039099&nsid=50910794@N07&lang=en-us&format=rss_200");

$x = new SimpleXmlElement($content);

$ourItems = "";

foreach($x->channel->item as $entry) {

    $thumbParent   = $entry->children("media");
    $thumb         = $thumbParent->thumbnail->attributes();
    $thumbW        = $thumb['width']; 
    $thumbH        = $thumb['height']; 
    $thumbURL      = $thumb['url']; 

   $ourItems .= "<li>\n"
                    ."<a href='$entry->link' title='$entry->title'>\n"
                       ."<img src='" . $thumbURL . "' />\n"
                    ."</a>\n"
                 ."</li>\n";

}

return $ourItems;

请有人指出我正确的方向 - 谢谢！

Answer 1

尝试使用儿童功能：

 $thumbA = $item->children('media', true)->thumbnail->attributes();

 <media:thumbnail url="<?php echo ($thumbA['url']); ?>" />

php使用命名空间导航RSS Feed

1 个答案: