从while循环创建ID数组

时间:2012-05-01 05:07:57

标签: php arrays while-loop

我试图生成一个数组,但不知道如何去做。

我目前正在获取我的数据:

$query = mysql_query("SELECT * FROM users WHERE userEmail LIKE 'test@test.com'");
$row = mysql_fetch_array($query);

$query1 = mysql_query("SELECT * FROM categories");
while($row1 = mysql_fetch_array($query1)){

    $query2 = mysql_query("SELECT * FROM usersettings WHERE userId = ".$row['userId']." AND usersettingCategory".$row1['categoryId']." LIKE 'y'");
    $isyes = mysql_num_rows($query2);

    if($isyes > 0){

        $cat1 = mysql_query("SELECT * FROM shops WHERE shopstateId = 1 AND (categoryId1 = ".$row1['categoryId']." OR categoryId2 = ".$row1['categoryId']." OR categoryId3 = ".$row1['categoryId'].")");
        $cat1match = mysql_num_rows($cat1);

        if($cat1match > 0){
            while($cat1shop = mysql_fetch_array($cat1)){
                $cat1msg = mysql_query("SELECT * FROM messages WHERE shopId = ".$cat1shop['shopId']." and messagestateId = 1");
                while($cat1msgrow = mysql_fetch_array($cat1msg)){

                    echo $cat1msgrow['messageContent']." - ".$cat1msgrow['messageCode'];
                    $cat1img = mysql_query("SELECT shopimagePath FROM shopimages WHERE shopimageId = ".$cat1shop['shopimageId']);
                    $imgpath = mysql_fetch_array($cat1img);
                    echo " - ".$imgpath['shopimagePath']."<br/>";
                }
            }
        }
     }
}

但是当用户在其偏好中选择了所有3个商店类别时,这可能会导致重复。我试图找到一种方法来将消息ID拉出而不是整个事物并将其放入一个给我的数组中,例如:

1,3,5,7,1,3,5,2,4,7,8

然后我可以运行一个单独的查询来告诉我所有消息,其中ID在数组中,但我不确定构建这样一个数组的最有建设性的方法和我已经看到的while循环的数组示例似乎不是我想要的。

那里有没有人可以把我推向正确的方向?

2 个答案:

答案 0 :(得分:0)

无法使用此代码。但是,如果您想要查询中没有重复结果的数组,可以在查询中使用“select DISTINCT(id)”或更简单的解决方案:

$id_arr = array();
$sql = mysql_query("select id from id_table"); 
while ($id_result = mysql_fetch_array($sql) {
  $id  = $id_result['id'];
  if (!in_array($id, $id_arr)) {
    $id_arr[] = $id;
  }
}

答案 1 :(得分:0)

我找到了一种更简单的方法来创建所需的结果。我认为在经过艰苦的夜间编码后的早上6点,我的大脑被炒了,而且我制作的东西比我需要的要复杂得多。我的问题的简单解决方案如下:

$query = mysql_query("SELECT * FROM users WHERE userEmail LIKE 'test2@test2.com'");
$row = mysql_fetch_array($query);

$categories = "(";

$query1 = mysql_query("SELECT * FROM categories");
while($row1 = mysql_fetch_array($query1)){

    $query2 = mysql_query("SELECT usersettingCategory".$row1['categoryId']." FROM usersettings WHERE userId = ".$row['userId']);
    $row2 = mysql_fetch_array($query2);

    if($row2['usersettingCategory'.$row1['categoryId']] == y){

        $categories .= $row1['categoryId'].",";
    }

}

$categories = substr_replace($categories ,")",-1);

echo $categories."<br />";

$query3 = mysql_query("SELECT * FROM shops,messages WHERE shops.shopId = messages.shopId AND messages.messagestateId = 1 AND (shops.categoryId1 IN $categories OR shops.categoryId2 IN $categories OR shops.categoryId3 IN $categories)");

while($row3 = mysql_fetch_array($query3)){

    $query4 = mysql_query("SELECT shopimagePath FROM shopimages WHERE shopimageId = ".$row3['shopimageId']);
    $row4 = mysql_fetch_array($query4);

    echo $row3['messageContent']." - ".$row3['messageCode']." - ".$row4['shopimagePath']."<br />";
}