用于搜索和替换的正则表达式

Question

我正在进行搜索和替换，需要替换不逗号","的所有字符。

如何按任意顺序搜索所有字符？

例如：

string, like , this 

......将成为：

replace,replace,replace,

Answer 1

匹配任何非逗号字符：[^，] +

所以perl：s / [^，] + / replace / g

Answer 2

在Perl中，您可以这样做：

my $string = "string, like , this";
my $replacement = "replace";
print $string, "\n";
$string =~ s/[^,]+/$replacement/g;
print $string, "\n";

Answer 3

您应该将匹配的文本括在括号中，然后将其替换为例如搜索：

([^,]+)

然后替换：

\1

与

replace

Answer 4

在vim中：

:%s/[^,]\+/replace/g

---

%            in the whole file
s            substitute
[^,]         match anything except comma
\+           match one or more times
/replace/    replace matched pattern with 'replace'
g            globally (multiple times on the same line)

Answer 5

在红宝石中：

original = "string, like , this"
substituted = original.gsub(/[^,]+/, 'replace')