Question

我是PHP的新手并获得消息Parse错误：语法错误，第25行的意外T_VARIABLE ..如果有人可以帮我解决这个错误，我会非常感激，因为它真的开始强调我。在Dreamweaver上，它说错误，它说$ Username = ...但我似乎无法修复它

<?php
    $host="******"; // Host name 
    $username="******"; // Mysql username 
    $password="******"; // Mysql password 
    $db_name="******"; // Database name 
    $tbl_name="avaya"; // Table name

    mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
    mysql_select_db("$db_name")or die("cannot select DB");


    $con = mysql_connect("localhost","root","");
    if (!$con)
      {
      die('Could not connect: ' . mysql_error());
      }
    mysql_select_db("inventory", $con);


    $addavaya="INSERT INTO avaya_pabx(critical_spare_id, serial_no, ,comcode, version, circuit_pack, classification, location, availability, date, client)
    VALUES ('". $_POST['critical_spare_id'] . "', '" . $_POST['serial_no']. "', '". $_POST['comcode'] . "','". $_POST['version'] . "','". $_POST['circuitp_pack'] . "','". $_POST['classification'] . "','". $_POST['location'] . "', '". $_POST['availability'] . "', '". $_POST['date'] . "', '". $_POST['client'] . "')";

    mysql_query($addavaya,$con)

    if (!mysql_query($addavaya,$con))
      {
      die('Error: ' . mysql_error());
      }
    echo "1 record added";

    mysql_close($con);

    ?>

Answer 1

你在这行末尾错过了一个分号：

mysql_query($addavaya,$con)

解析错误：语法错误，第25行的C：\ Program Files（x86）\ EasyPHP-5.3.9 \ www \ Inventory \ addclient.php中的意外T_IF

1 个答案: