在两个视图之间传递值 - Xcode 4.2与故事板

时间:2012-04-29 10:29:08

标签: uitableview xcode4.2 storyboard

我是使用storyboard进行Xcode编程的新手。 我正在尝试将值(标签的文本)传递给“SecondViewController”中的“View Controller”。 这是我的代码:

ViewController.m

- (IBAction)showSecondView:(id)sender {
    NSLog(@"Trying..");
    // The identifier used here is set on the second view controller in the UIStoryboard.
    SecondViewController *svc = [self.storyboard instantiateViewControllerWithIdentifier:@"SecondIdentifier"];
    NSLog(@"Test: %@",svc.labelTest.text);  //this print NIL!!
    svc.labelTest.text = @"GOOFY!!";
    [self.navigationController pushViewController:svc animated:YES];
}

SecondViewController.h

#import <UIKit/UIKit.h>

@interface SecondViewController : UIViewController

- (IBAction)returnToFirstView:(id)sender;
- (IBAction)toTabBar:(id)sender;
@property (strong, nonatomic) IBOutlet UILabel *labelTest;

@end

SecondViewController.m

#import "SecondViewController.h"

@implementation SecondViewController
@synthesize labelTest;

- (id)initWithNibName:(NSString *)nibNameOrNil bundle:(NSBundle *)nibBundleOrNil
{
    self = [super initWithNibName:nibNameOrNil bundle:nibBundleOrNil];
    if (self) {
        // Custom initialization
    }
    return self;
}

有人可以帮我吗? 非常感谢你!

斯特凡诺

1 个答案:

答案 0 :(得分:1)

如果您使用的是故事板,为什么不使用- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {

替换您的- (IBAction)showSecondView:(id)sender { - 方法

with:

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
if ([segue.identifier isEqualToString:@"SecondIdentifier"]) {
SecondViewController *svc = (SecondViewController *)segue.destinationViewController;
svc.labelTest.text = @"Goofy";
}