Question

我正在尝试配置一个简单的DbHelper，并在执行时收到错误。

错误是：

 SQLiteException near "null": syntax error: , while compiling: INSERT OR REPLACE INTO

我无法弄清楚问题是什么？

DbHelper类是：

    package com.sqlite.test1;

    import android.content.Context;
    import android.database.sqlite.SQLiteDatabase;
    import android.database.sqlite.SQLiteOpenHelper;

    public class DbHelper extends SQLiteOpenHelper{


    public static final int DB_VERSION = 1;
    public static final String DB_NAME = "time_storage";
    public static final String DB_TABLE = "timer_data";

    public static final String C_ID = "iderty_id";
    public static final String C_DATE = "date";
      Context context;

    public DbHelper(Context context) {
        super(context, DB_NAME, null, DB_VERSION);
        this.context = context;
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
        db.execSQL("create table if not exists " + DB_TABLE + " (" + C_ID + "integer primary key autoincrement, " 
                    + C_DATE + " text not null );");

    }

    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
        db.execSQL("DROP TABLE IF EXISTS " + DB_TABLE);
        this.onCreate(db);      
    }}

主要课程是：

package com.sqlite.test1;

import android.app.Activity;
import android.content.ContentValues;
import android.database.sqlite.SQLiteDatabase;
import android.os.Bundle;

public class SQlite_test1Activity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    DbHelper dbHelper = new DbHelper(SQlite_test1Activity.this);
    SQLiteDatabase db = dbHelper.getWritableDatabase();

    String variable1 = "this is the first text to database";
    ContentValues values = new ContentValues();
    db.insertWithOnConflict(DbHelper.DB_TABLE, null, values,
            SQLiteDatabase.CONFLICT_REPLACE);
    values.put(DbHelper.C_DATE, variable1);

    db.close();
    dbHelper.close();

}}

Answer 1

您需要在插入之前插入值，而不是之后，否则您不会插入任何内容。改变这个：

ContentValues values = new ContentValues();
db.insertWithOnConflict(DbHelper.DB_TABLE, null, values,
        SQLiteDatabase.CONFLICT_REPLACE);
values.put(DbHelper.C_DATE, variable1);

到此：

ContentValues values = new ContentValues();
values.put(DbHelper.C_DATE, variable1);
db.insertWithOnConflict(DbHelper.DB_TABLE, null, values,
        SQLiteDatabase.CONFLICT_REPLACE);

修改

发现了另一个问题：

db.execSQL("create table if not exists " + DB_TABLE + " (" + C_ID + "integer primary key autoincrement, " + C_DATE + " text not null );");

上面的代码正在创建一个名为iderty_idinteger的主键。它应该是这样的：

db.execSQL("create table if not exists " + DB_TABLE + " (" + C_ID + " integer primary key autoincrement, " + C_DATE + " text not null );");

请注意在integer primary ...
之前插入的空格

SQLiteException靠近“null”：语法错误：，同时编译：INSERT OR REPLACE INTO

1 个答案: