尝试打开联系人列表时出现问题?

时间:2012-04-28 20:18:41

标签: android contacts android-contacts

我在网上看到大量帖子显示“如何打开Android联系人列表”,但它们都已过时,部分代码甚至不再有效。

编辑:

现在有以下内容:

public class MessagePreview extends Activity {
final int PICK_CONTACT = 3;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Button recipientContact = (Button) findViewById(R.id.buttonAddRecipient);

    recipientContact.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            Intent intent = new Intent(Intent.ACTION_PICK,
                    ContactsContract.Contacts.CONTENT_URI);
            startActivityForResult(intent, PICK_CONTACT);
        }
    });

}

@Override
public void onActivityResult(int reqCode, int resultCode, Intent data) {
    super.onActivityResult(reqCode, resultCode, data);

    switch (reqCode) {
    case (PICK_CONTACT):
        if (resultCode == Activity.RESULT_OK) {
            Uri contactData = data.getData();
            Cursor c = managedQuery(contactData, null, null, null, null);
            if (c.moveToFirst()) {
                String name = c.getString(c
                        .getColumnIndexOrThrow(People.NAME));
                // TODO Whatever you want to do with the selected contact
                // name.
            }
        }
        break;
    }
}
 }

没有错误,但它确实说

  • 字段Contacts.PeopleColumns.NAME是  弃用
    • 类型Contacts.People已弃用
    • 字段Contacts.PeopleColumns.NAME是 弃用
    • 类型Contacts.People已弃用

在这一行:

String name = c.getString(c.getColumnIndexOrThrow(People.NAME));

我必须在该行之后添加更多代码,但我不知道要添加什么。

2 个答案:

答案 0 :(得分:0)

您正在尝试在另一个方法中定义方法。这不起作用。请将onActivityResult()的定义移至Activity上。

FWIW,here is a sample application选择适用于Android 1.5-4.0.3的联系人。

答案 1 :(得分:0)

String[] projection    = new String[] {ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,
                    ContactsContract.CommonDataKinds.Phone.NUMBER };
Cursor names = getContentResolver().query(contactData , projection, null, null, null);
int indexName = names.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
int indexNumber = names.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
names.moveToFirst();
do {
  String name   = names.getString(indexName);
  String number = names.getString(indexNumber);
} while (names.moveToNext());

在onactivityforresults上尝试此代码