Question

我有这个查询字符串......

select i.invoiceid, i.date, i.total, i.total - (select ifnull(sum(p.amount), 0) from payment p where p.invoice = i.invoiceid) as remainingbalance
        from invoice i inner join client c
        on i.client = c.clientid
        where i.isdeleted = 0 and i.client = 1
        union
        select p.paymentid, p.date, p.invoice, p.amount from payment p inner join invoice i
        on i.invoiceid = p.invoice
        inner join paymenttype
        on paymenttype.paymenttypeid = p.paymenttypeid
        inner join client c
        on c.clientid = i.client
        where c.clientid = 1
        and i.isdeleted = 0
        order by date

当我试着这个......

<?php
echo $clientArrayInvoice[1]['paymentid'];
?>

当我在$ clientArrayInvoice上执行print_r时，我得不到任何结果我得到了这个

Array ( [0] => Array ( [invoiceid] => 1 [date] => 2012-04-12 [total] => 602.29 [remainingbalance] => 300.96 ) [1] => Array ( [invoiceid] => 1 [date] => 2012-04-27 [total] => 1.00 [remainingbalance] => 301.33 ) )

我理解为什么要这样做，但是如何让列为{4}}而不是paymentid来表示返回的结果。所以我可以确定什么是invoiceid什么是paymentid我希望这是有道理的。

Answer 1

select i.invoiceid as transactionid, i.date, i.total, 
i.total - (select ifnull(sum(p.amount), 0) from payment p where p.invoice = i.invoiceid) as remainingbalance,
'invoice' as transaction_type
        from invoice i inner join client c
        on i.client = c.clientid
        where i.isdeleted = 0 and i.client = 1
        union
select p.paymentid as transactionid, p.date, p.invoice, p.amount, 'payment' as transaction_type
        from payment p inner join invoice i
        on i.invoiceid = p.invoice
        inner join paymenttype
        on paymenttype.paymenttypeid = p.paymenttypeid
        inner join client c
        on c.clientid = i.client
        where c.clientid = 1
        and i.isdeleted = 0
        order by date

SQL＆amp;用union查询PHP查询

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