Question

如果我的代码中有异常，我正在尝试实现一些重试逻辑。我已经编写了代码，现在我正在尝试让Rhino Mocks来模拟场景。代码的主旨如下：

class Program
    {
        static void Main(string[] args)
        {
            MockRepository repo = new MockRepository();
            IA provider = repo.CreateMock<IA>();

            using (repo.Record()) 
            {
                SetupResult.For(provider.Execute(23))
                           .IgnoreArguments()
                           .Throw(new ApplicationException("Dummy exception"));

                SetupResult.For(provider.Execute(23))
                           .IgnoreArguments()
                           .Return("result");
            }

            repo.ReplayAll();

            B retryLogic = new B { Provider = provider };
            retryLogic.RetryTestFunction();
            repo.VerifyAll();
        }
    }

    public interface IA
    {
        string Execute(int val);
    }

    public class B
    {
        public IA Provider { get; set; }

        public void RetryTestFunction()
        {
            string result = null;
            //simplified retry logic
            try
            {
                result = Provider.Execute(23);
            }
            catch (Exception e)
            {
                result = Provider.Execute(23);
            }
        }
    }

似乎发生的事情是每次抛出异常而不是一次抛出异常。我应该将设置更改为什么？

Answer 1

您需要使用Expect.Call而不是SetupResult：

        using (repo.Record())
    {
        Expect.Call(provider.Execute(23))
                   .IgnoreArguments()
                   .Throw(new ApplicationException("Dummy exception"));

        Expect.Call(provider.Execute(23))
                   .IgnoreArguments()
                   .Return("result");
    }

Rhino.Mocks维基说，

Using SetupResult.For() completely bypasses the expectations model in Rhino Mocks

犀牛嘲笑命令回复，抛出异常问题

1 个答案: