我可以使用c#
轻松创建平面序列化JSON字符串我的问题是我想创建一个如下所示的嵌套字符串
[ {
title: "Yes",
id : "1",
menu: [ {
title: "Maybe",
id : "3",
alert : "No",
menu: [ {
title: "Maybe Not",
id : "8",
alert : "No",
menu: []
} ]
} ]
},
{
title: "No",
id : "2",
menu: []
}]
任何帮助都会很棒
答案 0 :(得分:13)
您使用的是MVC 3吗? - 做类似的事情:
return Json(myObectWithListProperties, JsonRequestBehavior.AllowGet);
我用它来返回符合我想要的JavaScript对象结构的复杂C#对象。
e.g:
var bob = new {
name = "test",
orders = new [] {
new { itemNo = 1, description = "desc" },
new { itemNo = 2, description = "desc2" }
}
};
return Json(bob, JsonRequestBehavior.AllowGet);
给出:
{
"name": "test",
"orders": [
{
"itemNo": 1,
"description": "desc"
},
{
"itemNo": 2,
"description": "desc2"
}
]
}
编辑:为了好玩而筑巢一点:
var bob = new {
name = "test",
orders = new [] {
new { itemNo = 1, description = "desc" },
new { itemNo = 2, description = "desc2" }
},
test = new {
a = new {
b = new {
something = "testing",
someOtherThing = new {
aProperty = "1",
another = "2",
theThird = new {
bob = "quiteDeepNesting"
}
}
}
}
}
};
return Json(bob, JsonRequestBehavior.AllowGet);
给出:
{
"name": "test",
"orders": [
{
"itemNo": 1,
"description": "desc"
},
{
"itemNo": 2,
"description": "desc2"
}
],
"test": {
"a": {
"b": {
"something": "testing",
"someOtherThing": {
"aProperty": "1",
"another": "2",
"theThird": {
"bob": "quiteDeepNesting"
}
}
}
}
}
}
答案 1 :(得分:4)
尝试使用
using System.Web.Script.Serialization;
//Assumed code to connect to a DB and get data out using a Reader goes here
Object data = new {
a = reader.GetString(field1),
b = reader.GetString(field2),
c = reader.GetString(field3)
};
JavaScriptSerializer javaScriptSerializer = new JavaScriptSerializer();
string json = javaScriptSerializer.Serialize(data);
这是内置的,可以为您节省序列化到JSON的工作!
此示例假定您使用某种类型的读取器从数据库获取数据,然后使用匿名类构造要序列化的对象。您的匿名类可以像您需要的那样简单或复杂,JavaScriptSerializer将处理它转换为JSON。这种方法也很有用,因为您可以轻松地控制它将在JSON中创建的JSON属性名称。
答案 2 :(得分:1)
您可以使用ExpandoObject
命名空间下的System.Dynamic
。
以下是实现解决方案的小片段:
dynamic parameters = new dynamic[2];
parameters[0] = new ExpandoObject();
parameters[0].title = "Yes";
parameters[0].id = "1";
parameters[0].menu = new dynamic[1];
parameters[0].menu[0] = new ExpandoObject();
parameters[0].menu[0].title = "Maybe";
parameters[0].menu[0].id = "3";
parameters[0].menu[0].alert = "No";
parameters[0].menu[0].menu = new dynamic[1];
parameters[0].menu[0].menu[0] = new ExpandoObject();
parameters[0].menu[0].menu[0].title = "Maybe Not";
parameters[0].menu[0].menu[0].id = "8";
parameters[0].menu[0].menu[0].alert = "No";
parameters[0].menu[0].menu[0].menu = new dynamic[0];
parameters[1] = new ExpandoObject();
parameters[1].title = "No";
parameters[1].id = "2";
parameters[1].menu = new dynamic[0];
string json = JsonConvert.SerializeObject(parameters, Formatting.Indented);
Console.WriteLine(json);
注意:还有其他方法可以实现这一目标,但我一直在使用这种方法。
答案 3 :(得分:0)
using System.Web.Script.Serialization;
var strNJson = new
{
to = "hello",
notification = new
{
title = "textTitle",
body = "bodyText"
}
};
JavaScriptSerializer javaScriptSerializer = new JavaScriptSerializer();
string json = javaScriptSerializer.Serialize(strNJson);
{ "to":"hello",
"notification": {
"title":"titleText",
"body":"bodyText"
}
}