Question

我使用python 2.7和openCV 2.3.1（win 7）。我试着打开视频文件：

stream = cv.VideoCapture("test1.avi")
if stream.isOpened() == False:
print "Cannot open input video!"
exit()

但我有警告：

warning: Error opening file (../../modules/highgui/src/cap_ffmpeg_impl_v2.hpp:394)

如果使用摄像机（stream = cv.VideoCapture(0)），则此代码有效。关于我做错了什么的任何想法？非常感谢大家！

Answer 1

请尝试使用cv.CaptureFromFile()。

如果您必须：Watch Video in Python with OpenCV，请复制此代码。

Answer 2

你可以使用OpenCV（cv2）的新界面，这是一个面向对象的界面，它是从c ++绑定的。我发现它更容易，更易读。

注意：如果用这张打开图片，fps没有任何意义，所以图片保持不变。

import cv2
import sys

try:
    vidFile = cv2.VideoCapture(sys.argv[1])
except:
    print "problem opening input stream"
    sys.exit(1)
if not vidFile.isOpened():
    print "capture stream not open"
    sys.exit(1)

nFrames = int(vidFile.get(cv2.cv.CV_CAP_PROP_FRAME_COUNT)) # one good way of namespacing legacy openCV: cv2.cv.*
print "frame number: %s" %nFrames
fps = vidFile.get(cv2.cv.CV_CAP_PROP_FPS)
print "FPS value: %s" %fps

ret, frame = vidFile.read() # read first frame, and the return code of the function.
while ret:  # note that we don't have to use frame number here, we could read from a live written file.
    print "yes"
    cv2.imshow("frameWindow", frame)
    cv2.waitKey(int(1/fps*1000)) # time to wait between frames, in mSec
    ret, frame = vidFile.read() # read next frame, get next return code

Answer 3

从this answer开始，尝试将OpenCV安装中的所有.dll文件复制到C:\Python27。

用openCV + python打开视频

3 个答案: