对于像这样的json对象,
list=[
{name:"hello",
category:"verb"},
{name:"world",
category:"noun"}
];
使用下划线对阵列进行分类的最快方法是:
category=[
{id:"verb",
list:[
{name:"hello",
category:"verb"}
]},
{id:"noun",
list:[
{name:"world",
category:"noun"}
]}
];
它应该是某种链式map-reduce ...当然我可以使用_.filter
轻松地做到这一点(但这很慢),或使用for
循环。
答案 0 :(得分:1)
好的,我找到了:
groupBy _.groupBy(list,iterator)
将集合拆分为集合,按照通过迭代器运行每个值的结果进行分组。如果迭代器是字符串而不是函数,则按每个值上的迭代器命名的属性进行分组。
_.groupBy([1.3, 2.1, 2.4], function(num){ return Math.floor(num); });
=> {1: [1.3], 2: [2.1, 2.4]}
_.groupBy(['one', 'two', 'three'], 'length');
=> {3: ["one", "two"], 5: ["three"]}
所以我用它做了(我已经有了一个清单):
var listofwords=_.groupBy(doc.words, function(word){
return word.category;
});
_.each(doc.lists,function(list){
list.words=listofwords[list.name];
});
答案 1 :(得分:0)
我认为,这应该更快
list = [
{name:"hello", category:"verb"},
{name:"world", category:"noun"}
];
var addresses = {};
var catList = _.reduce(list, function(cat, item) {
var address = addresses[item.category];
if(typeof address == 'undefined') {
addresses[item.category] = address = cat.length;
cat.push({id: item.category, list: []});
}
cat[address].list.push(item);
return cat;
}, []);