Question

因此，我正在开发一个项目，为Pathfinder角色扮演游戏制作自动角色表，并且不知道如何保存数据。我想将所有变量的当前值保存到扩展名为.pfcsheet的文件中，稍后再打开。我已经google了，无法找到说明如何执行此操作的内容，只是如何保存文本框的内容。我尝试使用saveFileDialog控件，但它一直给我一个“文件名无效”错误，似乎没有人知道原因。

Answer 1

我刚写了a blog post on saving an object's data to Binary, XML, or Json。听起来您可能想要使用二进制序列化，但也许您希望在应用程序之外编辑文件，在这种情况下，XML或Json可能会更好。以下是以各种格式执行此操作的功能。有关详细信息，请参阅我的博文。

二进制

/// <summary>
/// Writes the given object instance to a binary file.
/// <para>Object type (and all child types) must be decorated with the [Serializable] attribute.</para>
/// <para>To prevent a variable from being serialized, decorate it with the [NonSerialized] attribute; cannot be applied to properties.</para>
/// </summary>
/// <typeparam name="T">The type of object being written to the XML file.</typeparam>
/// <param name="filePath">The file path to write the object instance to.</param>
/// <param name="objectToWrite">The object instance to write to the XML file.</param>
/// <param name="append">If false the file will be overwritten if it already exists. If true the contents will be appended to the file.</param>
public static void WriteToBinaryFile<T>(string filePath, T objectToWrite, bool append = false)
{
    using (Stream stream = File.Open(filePath, append ? FileMode.Append : FileMode.Create))
    {
        var binaryFormatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();
        binaryFormatter.Serialize(stream, objectToWrite);
    }
}

/// <summary>
/// Reads an object instance from a binary file.
/// </summary>
/// <typeparam name="T">The type of object to read from the XML.</typeparam>
/// <param name="filePath">The file path to read the object instance from.</param>
/// <returns>Returns a new instance of the object read from the binary file.</returns>
public static T ReadFromBinaryFile<T>(string filePath)
{
    using (Stream stream = File.Open(filePath, FileMode.Open))
    {
        var binaryFormatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();
        return (T)binaryFormatter.Deserialize(stream);
    }
}

XML

要求System.Xml程序集包含在项目中。

/// <summary>
/// Writes the given object instance to an XML file.
/// <para>Only Public properties and variables will be written to the file. These can be any type though, even other classes.</para>
/// <para>If there are public properties/variables that you do not want written to the file, decorate them with the [XmlIgnore] attribute.</para>
/// <para>Object type must have a parameterless constructor.</para>
/// </summary>
/// <typeparam name="T">The type of object being written to the file.</typeparam>
/// <param name="filePath">The file path to write the object instance to.</param>
/// <param name="objectToWrite">The object instance to write to the file.</param>
/// <param name="append">If false the file will be overwritten if it already exists. If true the contents will be appended to the file.</param>
public static void WriteToXmlFile<T>(string filePath, T objectToWrite, bool append = false) where T : new()
{
    TextWriter writer = null;
    try
    {
        var serializer = new XmlSerializer(typeof(T));
        writer = new StreamWriter(filePath, append);
        serializer.Serialize(writer, objectToWrite);
    }
    finally
    {
        if (writer != null)
            writer.Close();
    }
}

/// <summary>
/// Reads an object instance from an XML file.
/// <para>Object type must have a parameterless constructor.</para>
/// </summary>
/// <typeparam name="T">The type of object to read from the file.</typeparam>
/// <param name="filePath">The file path to read the object instance from.</param>
/// <returns>Returns a new instance of the object read from the XML file.</returns>
public static T ReadFromXmlFile<T>(string filePath) where T : new()
{
    TextReader reader = null;
    try
    {
        var serializer = new XmlSerializer(typeof(T));
        reader = new StreamReader(filePath);
        return (T)serializer.Deserialize(reader);
    }
    finally
    {
        if (reader != null)
            reader.Close();
    }
}

的Json

您必须包含对Newtonsoft.Json程序集的引用，该程序集可以从Json.NET NuGet Package获取。

/// <summary>
/// Writes the given object instance to a Json file.
/// <para>Object type must have a parameterless constructor.</para>
/// <para>Only Public properties and variables will be written to the file. These can be any type though, even other classes.</para>
/// <para>If there are public properties/variables that you do not want written to the file, decorate them with the [JsonIgnore] attribute.</para>
/// </summary>
/// <typeparam name="T">The type of object being written to the file.</typeparam>
/// <param name="filePath">The file path to write the object instance to.</param>
/// <param name="objectToWrite">The object instance to write to the file.</param>
/// <param name="append">If false the file will be overwritten if it already exists. If true the contents will be appended to the file.</param>
public static void WriteToJsonFile<T>(string filePath, T objectToWrite, bool append = false) where T : new()
{
    TextWriter writer = null;
    try
    {
        var contentsToWriteToFile = JsonConvert.SerializeObject(objectToWrite);
        writer = new StreamWriter(filePath, append);
        writer.Write(contentsToWriteToFile);
    }
    finally
    {
        if (writer != null)
            writer.Close();
    }
}

/// <summary>
/// Reads an object instance from an Json file.
/// <para>Object type must have a parameterless constructor.</para>
/// </summary>
/// <typeparam name="T">The type of object to read from the file.</typeparam>
/// <param name="filePath">The file path to read the object instance from.</param>
/// <returns>Returns a new instance of the object read from the Json file.</returns>
public static T ReadFromJsonFile<T>(string filePath) where T : new()
{
    TextReader reader = null;
    try
    {
        reader = new StreamReader(filePath);
        var fileContents = reader.ReadToEnd();
        return JsonConvert.DeserializeObject<T>(fileContents);
    }
    finally
    {
        if (reader != null)
            reader.Close();
    }
}

实施例

// To save the characterSheet variable contents to a file.
WriteToBinaryFile<CharacterSheet>("C:\CharacterSheet.pfcsheet", characterSheet);

// To load the file contents back into a variable.
CharacterSheet characterSheet = ReadFromBinaryFile<CharacterSheet>("C:\CharacterSheet.pfcsheet");

Answer 2

我想你可能想要这样的东西

// Compose a string that consists of three lines.
string lines = "First line.\r\nSecond line.\r\nThird line.";

// Write the string to a file.
System.IO.StreamWriter file = new System.IO.StreamWriter("c:\\test.txt");
file.WriteLine(lines);

file.Close();

Answer 3

查看XMLSerializer课程。

如果您想保存对象的状态并且能够在其他时间轻松地重新创建它们，那么序列化是您最好的选择。

序列化它，以便返回完整格式的XML。使用StreamWriter类将其写入文件。

稍后，您可以读入文件的内容，并将其与要填充的对象的实例一起传递给序列化程序类，并且序列化程序也将负责反序列化。

以下是从Microsoft Support获取的代码段：

using System;

public class clsPerson
{
  public  string FirstName;
  public  string MI;
  public  string LastName;
}

class class1
{ 
   static void Main(string[] args)
   {
      clsPerson p=new clsPerson();
      p.FirstName = "Jeff";
      p.MI = "A";
      p.LastName = "Price";
      System.Xml.Serialization.XmlSerializer x = new System.Xml.Serialization.XmlSerializer(p.GetType());

      // at this step, instead of passing Console.Out, you can pass in a 
      // Streamwriter to write the contents to a file of your choosing.
      x.Serialize(Console.Out, p);


      Console.WriteLine();
      Console.ReadLine();
   }
}

Answer 4

这是一个类似于萨钦的简单例子。建议使用＆＃34;使用＆＃34;非托管文件资源上的语句：

        // using System.IO;
        string filepath = @"C:\test.txt";
        using (StreamWriter writer = new StreamWriter(filepath))
        {
            writer.WriteLine("some text");
        }

using Statement (C# Reference)

Answer 5

以下是MSDN上有关如何将文本写入文件的指南的文章：

http://msdn.microsoft.com/en-us/library/8bh11f1k.aspx

我会从那里开始，然后在您继续开发时发布其他更具体的问题。

Answer 6

从System.IO命名空间（特别是File或FileInfo对象）开始，应该可以帮助您入门。

http://msdn.microsoft.com/en-us/library/system.io.file.aspx

http://msdn.microsoft.com/en-us/library/system.io.fileinfo.aspx

Answer 7

一个班轮：

System.IO.File.WriteAllText(@"D:\file.txt", content);

如果文件不存在，则创建该文件，如果存在，则覆盖该文件。确保您具有写入该位置的适当权限，否则您将获得例外。

https://msdn.microsoft.com/en-us/library/ms143375%28v=vs.110%29.aspx?f=255&MSPPError=-2147217396

Write string to text file and ensure it always overwrites the existing content.

将数据保存到C＃中的文件

7 个答案:

二进制

XML

的Json

实施例