Question

型号：

class Person(models.Model):
   friends= models.ManyToManyField("self", blank=True, null=True)


friends = person.friends.order_by('friends__id')[:5]

我也尝试了

friends = Person.objects.filter(friends=obj).order_by('-friends__id')[:5]

我需要通过中间表id（pk）订购朋友。

Answer 1

直接使用中间表，它不再是查询集。

friends = [pf.to_person for pf in 
    person.friends.through.objects.filter(from_person=person)
    .select_related('to_person')
    .order_by('pk')]

或者您需要在订购部分中编写原始SQL。

person.friends.order_by(person.friends.through._meta.db_table+'.id')

Answer 2

friends = person.friends.order_by('pk')

In [20]: [f.pk for f in p.friends.order_by('-pk')]
Out[20]: [3, 2]

In [21]: p.pk
Out[21]: 1

In [22]: [f.pk for f in p.friends.order_by('pk')]
Out[22]: [2, 3]

django manytomany自我关系顺序由中间表id

2 个答案: