我想使用java将字符串输入转换为2,3,6,7,8,10,12,14,15,16到2-3,6-8,10,12,14-16
我尝试使用以下代码
Vector ar=new Vector();
int lastadded=0;
String ht="";
String [] strarray=str.split(",");
strarray=sortArray(strarray);
Vector intarray=new Vector();
for(int i=0;i<strarray.length;i++)
{
int temp=1;
for(int j=1;j<=intarray.size();j++)
{
if(Integer.parseInt(strarray[i])==Integer.parseInt(intarray.get(j-1).toString()))
{
temp=0;
}
}
if(temp==1)
{
intarray.add(Integer.parseInt(strarray[i]));
ar.add(Integer.parseInt(strarray[i]));
}
}
ht="";
String strdemo="";
for(int i=0;i<intarray.size();i++)
{
if(ht=="")
{
ht=ar.get(i)+"";
lastadded=i;
}
else
{
strdemo=(String)ht;
if(strdemo.length()==ar.get(0).toString().length())
{
if(Integer.parseInt(strdemo.substring(0))==Integer.parseInt(ar.get(i).toString())-1)
{
strdemo=strdemo+"-"+ar.get(i);
lastadded=Integer.parseInt(ar.get(i).toString());
ht=strdemo;
}
else
{
strdemo=strdemo+","+ar.get(i);
lastadded=Integer.parseInt(ar.get(i).toString());
ht=strdemo;
}
}
else if(strdemo.length()==3)
{
strdemo=(String)ht;
if(Integer.parseInt(strdemo.substring(strdemo.length()-1,strdemo.length()))==Integer.parseInt(ar.get(i).toString())-1)
{
strdemo=strdemo.substring(0,strdemo.length()-2)+"-"+Integer.parseInt(ar.get(i).toString());
lastadded=Integer.parseInt(ar.get(i).toString());
ht=strdemo;
}
else
{
strdemo=strdemo+","+Integer.parseInt(ar.get(i).toString());
lastadded=Integer.parseInt(ar.get(i).toString());
ht=strdemo;
}
}//Else IF
else{
strdemo=(String)ht;
int de=1;
int ddd=lastadded;
if(ddd==Integer.parseInt(ar.get(i).toString())-1)
{
int lastaddedlen=(lastadded+"").length();
String symbol=strdemo.substring(strdemo.length()-lastaddedlen-1,strdemo.length()-lastaddedlen);
if(symbol.equalsIgnoreCase("-"))
strdemo=strdemo.substring(0,strdemo.length()-lastaddedlen-1)+"-"+Integer.parseInt(ar.get(i).toString());
else
strdemo=strdemo+"-"+Integer.parseInt(ar.get(i).toString());
lastadded=Integer.parseInt(ar.get(i).toString());
ht=strdemo;
}
else
{
strdemo=strdemo+","+Integer.parseInt(ar.get(i).toString());
lastadded=Integer.parseInt(ar.get(i).toString());
ht=strdemo;
}
}
}
}
此处sortArray函数对数组进行降序排序并返回
protected static String[] sortArray(String ss[])
{
String temp;
for(int i=0;i<ss.length;i++)
{
for(int j=0;j<ss.length;j++)
{
if(Integer.parseInt(ss[i])<Integer.parseInt(ss[j]))
{
temp=ss[i];
ss[i]=ss[j];
ss[j]=temp;
}
}
}
return ss;
}
对于某些输入，我没有得到一致的结果，例如以下情况
2,3,6,7,8,10,12,14,15,16它提供了2-3,6-8,10,12,14-16（，这是正确的）
而对于2,4,5,6,7,8,10,12,14,15,16，它会2-8,10,12,14-16 (which actually should have been 2,4-8,10,12,14-16 )
代码不一致的地方是我需要找到的......
答案 0 :(得分：3)
这在Java中非常丑陋和冗长，但这是一个版本。注意，它在最后使用Spring中的StringUtils来处理将String集合转换为逗号分隔字符串的简单而又丑陋的过程。
关键是使用单独的类来模拟数值范围。让这个类知道如何将自己变成一个String。那么你就不会有如此多的逻辑来附加到StringBuilder。
另外，尝试从集合的角度思考。这总能让事情更加清晰。伪代码类似于：String变为List<Integer>变为List<Range>，最后变为String。
public class Ranges {
// A class that models a range of integers
public static class Range {
private int low;
private int high;
public Range(int low, int high) {
this.low = low;
this.high = high;
}
public int getHigh() {
return high;
}
public void setHigh(int high) {
this.high = high;
}
@Override
public String toString() {
return (low == high) ? String.valueOf(low) : String.format("%d-%d", low, high);
}
}
public static void main(String[] args) {
String input = "2,3,6,7,8,10,12,14,15,16";
// Turn input string into a sorted list of integers
List<Integer> inputNumbers = new ArrayList<Integer>();
for (String num : input.split(",")) {
inputNumbers.add(Integer.parseInt(num));
}
Collections.sort(inputNumbers);
// Flatten list of integers into a (shorter) list of Ranges
Range thisRange = null; // the current range being built
List<Range> ranges = new ArrayList<Range>();
for (Integer number : inputNumbers) {
if (thisRange != null && number <= thisRange.getHigh() + 1) {
// if we are already building a range (not null) && this new number is
// the old high end of the range + 1, change the high number.
thisRange.setHigh(number);
} else {
// create a new range and add it to the list being built
thisRange = new Range(number, number);
ranges.add(thisRange);
}
}
// Join List<String> into a single String
String result = StringUtils.collectionToCommaDelimitedString(ranges);
System.out.println("result = " + result);
}
}
答案 1 :(得分：0)
这是我的实施。希望这有帮助。
您必须传递这些值
例如int[] a = {2,3,4,5,6,7,8,10,12, 14,15,16,18,19,21,22,26};
以下方法。
public List<String> listIntRange(int[] values)
{
List<String> intRangeList = new ArrayList<String>();
int first = 0;
int current = 0;
int prev = 0;
int count = 0;
if (values == null || values.length < 1)
return intRangeList;
first = prev = values[0];
int index = 1;
boolean range = false;
for(index = 1; index < values.length; index++)
{
current = values[index];
if(current - prev == 1)
{
range = true;
prev = current;
continue;
}
if(range == true)
{
intRangeList.add(first + "-" + prev);
}
else
{
intRangeList.add("" + first);
}
first = current;
prev = current;
range = false;
}
if(range == true)
{
intRangeList.add(first + "-" + current);
}
else
{
intRangeList.add("" + current);
}
return intRangeList;
}
当打印出intRangeList：
中的值时，输出如下所示2-8,10,12,14-16,18-19,21-22,26,
请忽略最后一个逗号'，'。