传递变量时GeoPoint无法正常工作

Question

我和Android / Java新手在创建GeoPoint时遇到了麻烦，当我尝试向它发送一个变量时，但是当我发送一个字面值时它会很好。

在下面的代码块中，toast消息显示正确的纬度（从strings.xml

中检索）

如何使用变量设置谷歌纵横？

Integer intLat = Integer.valueOf(R.string.MexCityLat);
Toast.makeText(HelloGoogleMapsActivity.this, intLat, Toast.LENGTH_SHORT).show();

GeoPoint point = new GeoPoint(intLat , -99120000);  //this puts my point near North Pole
//GeoPoint point = new GeoPoint(19240000, -99120000);  //this puts my point in Mexico City

OverlayItem overlayitem = new OverlayItem(point, "Hola, Mundo!", "I'm in Mexico City!");

Answer 1

<强>的GeoPoint

public GeoPoint(int latitudeE6,int longitudeE6)

构造一个具有给定纬度和经度的GeoPoint，以微度（度* 1E6）为单位。

<强>参数：

 latitudeE6 - The point's latitude. This will be clamped to between -80 degrees and +80 degrees inclusive, in order to maintain accuracy in the Mercator projection.
 longitudeE6 - The point's longitude. This will be normalized to be greater than -180 degrees and less than or equal to +180 degrees.

另请参阅此link了解如何将double，float转换为geopoint。并确保你获得了正确的intLat值