为什么我的程序找不到要打开的文本文件?

时间:2012-04-25 23:33:24

标签: ruby

我正在为Ruby中的CS赋值编写此代码。我刚刚开始使用Ruby,所以我对它并不了解,但我不断从这段代码中得到一个no方法错误:

V:\CS 300 RubyAssignment\lib\rubyAssignment.rb:13:in `categorize': undefined method `line' for #<File:ruby1.txt (closed)> (NoMethodError)
    from V:\CS 300 RubyAssignment\lib\rubyAssignment.rb:11:in `open'
    from V:\CS 300 RubyAssignment\lib\rubyAssignment.rb:11:in `categorize'
    from V:\CS 300 RubyAssignment\lib\rubyAssignment.rb:30

代码如下,但我感觉我的文本文件位于错误的位置。我使用NetBeans Ruby插件,我不知道我的文本文件是否应该在netbeans中的项目源文件夹,测试文件夹或库文件夹中?它可能就像任何想法一样简单吗?

# This program reads a file line by line,
# separating lines by writing into certain text files.
# PPQ - Pangrams, Palindromes, and Quotes

class PPQ
  def categorize
    file_pangram = File.new('pangram.txt', 'w')
    file_palindrome = File.new('palindrome.txt', 'w')
    file_quotes = File.new('quotes.txt','w')

    File.open('ruby1.txt','r') do |file|
      while line = file.gets
        if(file.line.reverse == file.line)
          file_palindrome.write line
          if(file.line.contains('a'&&'b'&&'c'&&'d'&&'e'&&'f'&&'g'&&'h'&&'i'&&'j'&&'k'&&'l'&&'m'&&'n'&&'o'&&'p'&&'q'&&'r'&&'s'&&'t'&&'u'&&'v'&&'w'&&'x'&&'y'&&'z'))
            file_pangram.write "file.line"
          else
            file_quotes.write "file.line"
          end
        end
      end
      file.close
      file_pangram.close
      file_palindrome.close
      file_quotes.close
    end
  end
end
my_ruby_assignment = PPQ.new
my_ruby_assignment.categorize

1 个答案:

答案 0 :(得分:1)

错误消息中的线索!

undefined method line

在您的while循环中,您正在通过filegets读取一行,然后将其存储在line中。这段代码:

if(file.line.reverse == file.line)

因此不正确 - 您不需要file.前缀! Ruby认为你试图调用它没有的line对象的file方法。这就是为什么它给你的错误...