Enterprise构建和UUID使用问题

时间:2012-04-25 19:43:14

标签: iphone ios ipad keychain udid

如您所知,Apple最近弃用了UDID。所以我对此的解决方案是

  1. 生成CFUUID
  2. 将其保存到钥匙串
  3. 之后重新访问钥匙串项目。
  4. 这一直很好。但是,出于某种原因,我们最近看到,随着企业版本的安装,我们得到了一个不同的UUID(应该使用我们唯一的访问密钥存储在钥匙串上)。

    有人遇到过这样的情况吗?这是创建UUID并将其存储到钥匙串的代码..

    + (NSString *)registerUUIDWithKeyChain
    {
    CFUUIDRef udid = CFUUIDCreate(NULL);
    NSString *uuidString = (NSString *) CFUUIDCreateString(NULL, udid);
    
    KeychainItemWrapper *keychainItem = [[KeychainItemWrapper alloc] initWithIdentifier:@"UniqueApp" accessGroup:nil];
    
    NSString *userName = @"UniqueAppName";
    NSString *password = uuidString;
    
    [keychainItem setObject:userName forKey:(id)kSecAttrAccount];
    [keychainItem setObject:password forKey:(id)kSecValueData];
    
    [keychainItem release]; 
    
    return uuidString;
    
    }
    
    + (NSString *)userUUID
    {
        KeychainItemWrapper *keychainItem = [[KeychainItemWrapper alloc] initWithIdentifier:@"UniqueApp" accessGroup:nil];
    
    //Accesing the v_data was the only way. For some reason there is a runtime issue if we try to access it though "kSecValueData"
    NSString *uuid = [keychainItem.keychainItemData objectForKey:@"v_Data"];
    
    //Check if the app is installed for the first time on the device. If YES register the UUID in to the keychain.
    //Also check if it is a reinstall by accessing the previous keyChainItem with our Identifier.
    if ([[[NSUserDefaults standardUserDefaults] valueForKey:@"firstRun"] intValue] == 0 && !(uuid.length > 0)) 
    {
        uuid = [UIDevice_Additions registerUUIDWithKeyChain];
    
        NSLog(@"\n First Time Registered UUID is %@", uuid);
    
        //after stuff done
        [[NSUserDefaults standardUserDefaults] setValue:[NSNumber numberWithInt:1] forKey:@"firstRun"];
        [[NSUserDefaults standardUserDefaults] synchronize];
    
        [keychainItem release]; 
        return uuid;
    }
    
    [keychainItem release]; 
    return uuid;
    }
    
    @end
    

2 个答案:

答案 0 :(得分:3)

Okie,

在与这个问题争夺一天之后,我发现了触发这个问题的原因。

  • 钥匙串是依赖证书的
  • 使用不同的证书创建企业版本
  • 因此,当代码尝试从企业版本访问您的密钥时,您将找不到它,因此生成的代码将生成一个新代码。
  • 解决方案是创建您的钥匙串,以便全局访问。您可以在KeyChainWrapper init方法中更改accessGroup变量。

祝你好运!

答案 1 :(得分:-3)

您可以使用MAC地址而不是UUID

- (NSString *) macaddress
{
    int                 mib[6];
    size_t              len;
    char                *buf;
    unsigned char       *ptr;
    struct if_msghdr    *ifm;
    struct sockaddr_dl  *sdl;

    mib[0] = CTL_NET;
    mib[1] = AF_ROUTE;
    mib[2] = 0;
    mib[3] = AF_LINK;
    mib[4] = NET_RT_IFLIST;

    if ((mib[5] = if_nametoindex("en0")) == 0) {
        printf("Error: if_nametoindex error\n");
        return NULL;
    }

    if (sysctl(mib, 6, NULL, &len, NULL, 0) < 0) {
        printf("Error: sysctl, take 1\n");
        return NULL;
    }

    if ((buf = malloc(len)) == NULL) {
        printf("Could not allocate memory. error!\n");
        return NULL;
    }

    if (sysctl(mib, 6, buf, &len, NULL, 0) < 0) {
        printf("Error: sysctl, take 2");
        return NULL;
    }

    ifm = (struct if_msghdr *)buf;
    sdl = (struct sockaddr_dl *)(ifm + 1);
    ptr = (unsigned char *)LLADDR(sdl);
    NSString *outstring = [NSString stringWithFormat:@"%02X:%02X:%02X:%02X:%02X:%02X", 
                           *ptr, *(ptr+1), *(ptr+2), *(ptr+3), *(ptr+4), *(ptr+5)];
    free(buf);

    return outstring;
}