Question

请原谅我，如果这已经得到回答/非常基本/问题措辞错误，我对此非常陌生并且在努力。

基本上我有生成XML的后端PHP，然后Flash构建器继承数据。我遇到的问题是了解Flash构建器如何通过HttpService向PHP发送参数，例如

这是它目前所解释的：

http://..../file.php?action=getitems

我希望Flash构建器发送的是

&class=fruit (<- the class would be dependant on what is selected from the drop down in the application)

整体创建此字符串

http://..../file.php?action=getitems&class=fruit

如果这是胡说八道，谢谢你并道歉。我正在使用Flash Builder 4。

Answer 1

总的来说，我会使用push方法而不是传递变量，从而减少从中间被黑客入侵的可能性。

http呼叫的AS3代码：

    public function someRequest() : void
    {
        var service : HTTPService = new HTTPService();
        service.url = "http://localhost/getData.php";
        service.useProxy = false;
        service.method = "POST";
        service.contentType = "application/xml";    // Pass XML data.
        service.request = "<ID>somevalue</ID>";     // The XML data.
        service.resultFormat = "xml";               // Recieve XML data.
        service.addEventListener(ResultEvent.RESULT, createFields);
        service.addEventListener(FaultEvent.FAULT, handleFault);
        service.send();
    }

    private function createFields(event : ResultEvent) : void
    {
        var result : String = event.result.toString();
        returnData = XML(result);
    }

    private function handleFault(event : FaultEvent) : void
    {
        var faultstring : String = event.fault.faultString;
        Alert.show(faultstring);
    }

正如您在中间看到的那样，有一个用于输入变量的XML空间。我使用这种方法将数据从PHP传递到AS3。

PHP是：

<?php

define("DATABASE_SERVER", "localhost");
define("DATABASE_USERNAME", "root");
define("DATABASE_PASSWORD", "**");
define("DATABASE_NAME", "dbName");

//connect to the database.
$mysql = mysql_connect(DATABASE_SERVER, DATABASE_USERNAME, DATABASE_PASSWORD);

mysql_select_db(DATABASE_NAME);

$Query  = "SELECT * from data WHERE employeeID = '" . ($_POST['ID']) . "'";
$Result = mysql_query($Query);

$Return = "<data>";

while ($User = mysql_fetch_object($Result))
{
    $Return .= "<user><userid>" . $User->userid . "</userid><username>" . $User->username . "</username><emailaddress>" . $User->emailaddress . "</emailaddress></user>";
}
$Return .= "</data>";
mysql_free_result($Result);
print ($Return)
?>

希望能帮到你。

Answer 2

这在Flex中实际上相当简单......

var service : HTTPService = new HTTPService();
service.url = "http://localhost/getData.php";
service.method = "POST";


var parameters:Object = new Object();
parameters["action"] = "getitems";
parameters["class"] = "fruit";

service.send(parameters);

......完成！

Answer 3

我通常通过[POST]代替[GET]

来处理这个问题

在你的动作函数中：

private function sendRequest():void {
var obj:Object = new Object();
obj.action="getitems";
obj.class="fruit";

myService.send(obj);

您的httpService

<s:HTTPService id='myService' url='urlToYourPHP' method='POST' result='yourResultHandler' fault='yourFaultHandler' resultFormat='XML'/>

正如powelljf3所说，POST比GET更安全，尽管它仍然可以获得。

如何通过URL从Flex HttpService向PHP发送参数

3 个答案: