Question

我试图计算两个日期之间的小时数。当我运行应用程序时，它崩溃了。你能告诉我这段代码中的错误吗？

NSString *lastViewedString = @"2012-04-25 06:13:21 +0000";
NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[dateFormatter setDateFormat: @"yyyy-MM-dd HH:mm:ss zzz"];

NSDate *lastViewed = [[dateFormatter dateFromString:lastViewedString] retain];
NSDate *now = [NSDate date];

NSLog(@"lastViewed: %@", lastViewed); //2012-04-25 06:13:21 +0000
NSLog(@"now: %@", now); //2012-04-25 07:00:30 +0000

NSTimeInterval distanceBetweenDates = [now timeIntervalSinceDate:lastViewed];
double secondsInAnHour = 3600;
NSInteger hoursBetweenDates = distanceBetweenDates / secondsInAnHour;

NSLog(@"hoursBetweenDates: %@", hoursBetweenDates);

Answer 1

参考this answer of a mostly similar question一个更好的，Apple批准的方式是使用这样的NSCalendar方法：

- (NSInteger)hoursBetween:(NSDate *)firstDate and:(NSDate *)secondDate {
   NSUInteger unitFlags = NSCalendarUnitHour;
   NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
   NSDateComponents *components = [calendar components:unitFlags fromDate:firstDate toDate:secondDate options:0];
   return [components hour]+1;
}

如果您定位iOS 8或更高版本，请使用NSCalendarIdentifierGregorian而不是已弃用的NSGregorianCalendar。

Answer 2

我认为差异应该是int值......

NSLog(@"hoursBetweenDates: %d", hoursBetweenDates);

希望，这会对你有帮助..

Answer 3

使用

无法显示NSInteger

NSLog(@"%@", hoursBetweenDates);

改为使用：

NSLog(@"%d", hoursBetweenDates);

如果不确定使用Apple Developer Docs中的内容： http://developer.apple.com/library/mac/#documentation/Cocoa/Conceptual/Strings/Articles/formatSpecifiers.html#//apple_ref/doc/uid/TP40004265

两个NSDate之间的小时差异

3 个答案: