Question

我应该能够解决这个问题，但我一直在圈子里。我有一个带复选框的表单。选中复选框后，它们会被标记为删除。

我使用foreach处理这些选中的复选框：

foreach (array_keys($_POST['checkboxselect']) as $k) {
    $str .= $k.',';
}

这是我将视频列表放在一起的蹩脚尝试。我正在使用的sql删除是：

DELETE FROM `videos` WHERE `video_name` IN ($str)

所以我在这里遗漏了很多东西。 $str需要：

只返回一个复选框，因此返回带引号的字符串（即“myvideo.mp4”）
选中了多个复选框，因此使用引号和逗号构建一个字符串（即“myvideo.mp4”，“myvideo2.mp4”，“myvideo3.mp4”）

感谢您的帮助。

Answer 1

像这样使用implode()：

$str = '"' . implode('","', array_keys($_POST['checkboxselect'])) . '"';

implode()将获取一个数组并使用“glue”字符串连接数组中的每个值。在这种情况下，“胶水”是","，数组由$_POST['checkboxselect']中的键组成。最后，生成的字符串包含在"。

中

这将产生您想要的示例字符串"myvideo.mp4","myvideo2.mp4","myvideo3.mp4"。

Answer 2

尝试使用PHP的implode：

// Init links
$mysqliLink = mysqli_connect('host', 'user', 'password') or die('Could not connect: ' . mysqli_error());

$mysqlLink = mysql_connect('host', 'user', 'password') or die('Could not connect: ' . mysql_error());

//-----
// Prep values for query
//-----

// Only pick one of the following depending upon the mysql library you are using

// If using mysql, passing the 2nd argument is not necessary, but for 
// clarity, adding it
$deleteNames = array_map('mysql_real_escape_string', array_keys($_POST['checkboxselect']), array_fill(0, count($_POST['checkboxselect']), $mysqlLink));

// If using mysqli
// This will ensure that $mysqliLink will be passed in as first arg for 
// every iteration satisfying the function signature
$deleteNames = array_map('mysqli_real_escape_string', array_fill(0, count($_POST['checkboxselect']), $mysqliLink), array_keys($_POST['checkboxselect']));
//-----


// Because you are passing strings, we need to ensure each is wrapped in quotes
$deleteNames = "'" . implode("','", $deleteNames) . "'";

// Construct query using implode
$sql = sprintf('DELETE FROM `videos` WHERE `video_name` IN (%s)', $deleteNames);

- 更新 -

使用Joomla API：

$db = &JFactory::getDBO();

// Localize and sanitize each individual value
foreach (array_keys($_POST['checkboxselect']) as $element) {
    $deleteNames[] = $db->quote($element);
}

// Because you are passing strings, we need to ensure each is wrapped in quotes
// No longer true because $db->quote taking care of quoting out each name for us
$deleteNames = implode(',', $deleteNames);

// Construct query using implode
$sql = sprintf('DELETE FROM `videos` WHERE `video_name` IN (%s)', $deleteNames);

在php foreach中连接字符串

2 个答案: