我需要这样的东西,
SELECT CLIENT_AHCCCS_ID + CLIENT_FIRST_NAME + CLIENT_LAST_NAME + replace(convert(datetime, DATE_OF_BIRTH, 1), '/', '')
FROM tblCLIENT
WHERE CLIENT_AHCCCS_ID IS NOT NULL AND CLIENT_AHCCCS_ID LIKE 'A%'
但必须确保
CLIENT_AHCCCS_ID ( 9 character )
Member Last Name ( 25 character )
First Name ( 25 character )
我必须使用空格来填充字符串。我怎么能做到这一点?
答案 0 :(得分:4)
假设SQL Server,SQL数据类型char填充字符串,因此您始终可以转换为:
SELECT
CONVERT(char(9), CLIENT_AHCCCS_ID) +
CONVERT(char(25), CLIENT_FIRST_NAME) +
CONVERT(char(25), CLIENT_LAST_NAME) +
replace...